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postnew [5]
3 years ago
9

How many atoms are present in 23.0 g of carbon?

Chemistry
2 answers:
Bas_tet [7]3 years ago
4 0

Answer:  6.0225X10^23

Explanation:

Number of atoms in 24g of carbon

We know that Carbon has atomic mass equal to 12g, I. E. One mole of carbon atom weighs 12g. We know that one mole of any substance contains 6.0225X10^23 particles(atoms, molecules, ions, etc.). Thus 12g of Carbon contains 6.0225X10^23 atoms of Carbon

Elza [17]3 years ago
3 0

Answer: 6.0225X10^23

Explanation:

We know that Carbon has atomic mass equal to 12g, I. E. One mole of carbon atom weighs 12g. We know that one mole of any substance contains 6.0225X10^23 particles(atoms, molecules, ions, etc.). Thus 12g of Carbon contains 6.0225X10^23 atoms of Carbon.

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- Explain how ionic bonds, covalent bonds, and metallic bonds each form and how.
-Dominant- [34]

Answer:  -Ionic bonds form when one atom provides electrons to another atom. Covalent Bonds: Covalent bonds form when two atom shares their valence electrons. Metallic Bonds: Metallic bonds form when a variable number of atoms share a variable number of electrons in a metal lattice.

-Covalent Bonds.

Covalent Compounds. Contain no metals and no ions. Covalent compounds contain nonmetals only.

Example:

Ionic Compounds. A metal with a non-metal. Doesn't use prefixes for naming. Name the metal and change the nonmetal ending to -ide.

Explanation: Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

6 0
2 years ago
Why k has more shielding effect than Na?​
lara [203]

Explanation:

As the charge of all electrons are equal, the repulsive force exerted by each of them is also going to be equal. So, as K has more electrons repulsing its valence electron than Na, it has greater electron shielding.

8 0
3 years ago
A gas cylinder of volume 5.00 l contains 1.00 g of ar and 0.500 g of ne. the temperature is 275 k. find the partial pressure of
amid [387]
<span>11.3 kPa The ideal gas law is PV = nRT where P = Pressure V = Volume n = number of moles R = Ideal gas constant (8.3144598 L*kPa/(K*mol) ) T = Absolute temperature We have everything except moles and volume. But we can calculate moles by starting with the atomic weight of argon and neon. Atomic weight argon = 39.948 Atomic weight neon = 20.1797 Moles Ar = 1.00 g / 39.948 g/mol = 0.025032542 mol Moles Ne = 0.500 g / 20.1797 g/mol = 0.024777375 mol Total moles gas particles = 0.025032542 mol + 0.024777375 mol = 0.049809918 mol Now take the ideal gas equation and solve for P, then substitute known values and solve. PV = nRT P = nRT/V P = 0.049809918 mol * 8.3144598 L*kPa/(K*mol) * 275 K/5.00 L P = 113.8892033 L*kPa / 5.00 L P = 22.77784066 kPa Now let's determine the percent of pressure provided by neon by calculating the percentage of neon atoms. Divide the number of moles of neon by the total number of moles. 0.024777375 mol / 0.049809918 mol = 0.497438592 Now multiply by the pressure 0.497438592 * 22.77784066 kPa = 11.33057699 kPa Round the result to 3 significant figures, giving 11.3 kPa</span>
8 0
3 years ago
3
atroni [7]

Answer:

(1) atomic numbers

Explanation:

The observed regularities in the properties of the elements on the periodic table are periodic functions of their atomic numbers.

  • Atomic number is the number of protons in an atom.
  • The periodic law states that "the properties of elements are a periodic function of their atomic number".
  • Elements on the periodic table are arranged based on the atomic numbers they contain.
  • The number of positively charged particles in an atom is the atomic number.
6 0
2 years ago
This is the chemical formula for talc (the main ingredient in talcum powder): mg3(si2o5)2(oh)2. an analytical chemist fins that
weqwewe [10]
In one mole of talc, we observe that there are:
3 moles of Mg
4 moles of Si
2 moles of H
12 moles of O

The molar ratio of O to Mg is then:

12 moles of O : 3 moles of Mg = 4 : 1

Therefore, if 6.1 moles of Mg are present, the moles of O are:

4 * 6.1 = 24.4 moles of O
7 0
3 years ago
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