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postnew [5]
3 years ago
9

How many atoms are present in 23.0 g of carbon?

Chemistry
2 answers:
Bas_tet [7]3 years ago
4 0

Answer:  6.0225X10^23

Explanation:

Number of atoms in 24g of carbon

We know that Carbon has atomic mass equal to 12g, I. E. One mole of carbon atom weighs 12g. We know that one mole of any substance contains 6.0225X10^23 particles(atoms, molecules, ions, etc.). Thus 12g of Carbon contains 6.0225X10^23 atoms of Carbon

Elza [17]3 years ago
3 0

Answer: 6.0225X10^23

Explanation:

We know that Carbon has atomic mass equal to 12g, I. E. One mole of carbon atom weighs 12g. We know that one mole of any substance contains 6.0225X10^23 particles(atoms, molecules, ions, etc.). Thus 12g of Carbon contains 6.0225X10^23 atoms of Carbon.

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The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
a person measures the mass of an 8 cm3 block of brown sugar to be 12.9 g. What is the density of the brown sugar.
Maksim231197 [3]


From the information we have, this block of brown sugar  has a volume of 8cm3

The mass of the block is 12. 9 grams.

We need to find out the density of the sugar.

For a solid material the formula for calculating density is given as:

Density = mass / volume

Therefore we simply fit in the above given values into this formula, so:

Density = 12.9 / 8

Density = 1.61

Therefore the density of the block of sugar is 1.61g/ml


8 0
3 years ago
A student adds a rectangular block of mass 26.10 g to a graduated cylinder initially filled with 40.1 mL of water, but some wate
Amiraneli [1.4K]

Answer:

The splash cause the volume of the block to be too high

Explanation:

This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

8 0
2 years ago
The comparison of the masses of equal volumes of material is also defined as
Yuri [45]
Density, I am pretty sure this is the correct answer.
8 0
3 years ago
Which is a chemical property of vinegar? The pH of vinegar is around 2.4. Vinegar freezes at around 2°C. Vinegar boils at about
STatiana [176]
A chemical property would be its pH of 2.4.
all others are physical properties and aspect

hope that helps
4 0
3 years ago
Read 2 more answers
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