Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
Answer:
677.7 mmHg
Explanation:
This is Dalton's law, where you add each partial pressure into total.
You are given total pressure of 692.2 mmHg
Partical pressure of water is: 14.5 mmHg
To find the partial pressure of O2, you subtract the total pressure and the given vapor pressure of water.
If you want the answer in atm, it would be: 0.892 atm
677.7 mmHg X (1 atm/760 mmHg) = 0.892 atm
Hope this helps!
This is non polar because the elements are relatively close on the periodic table
Look that up on the Internet it will tell you