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o-na [289]
3 years ago
10

A wire 1 mm in diameter is connected to one end of a wire of the same material 2 mm in diameter of twice the length. A voltage s

ource is connected to the wires and a current is passed through the wires. If it takes time T for the average conduction electron to traverse the 1-mm wire, how long does it take for such an electron to traverse the 2-mm wire
Physics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

T = 2 T₀

Explanation:

To answer this question let's write the expression for electrical conductivity

    σ = n e2 τ / m*

The relationship with resistivity is

       ρ = 1 /σ

Whereby the resistance

        R = ρ L / A = 1 /σ  L / A

We see that there is no explicit relationship between time and resistance, there is only a dependence on the life time (τ) that depends on the properties of the material, not on its diameter or length.

As also the average velocity or electron velocity of electrons is constant, the time to cross 2 mm in length is twice as long as the time to cross a mm in length

 T = 2 T₀

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What is the mass of an object if a force of 34 N produces an acceleration of 4.0 m/s squared​
mrs_skeptik [129]

Answer:

8.5 kg

Explanation:

F = ma

34 N = m(4.0m/s^2)

m = 8.5 kg

6 0
3 years ago
Which of the following is a characteristic of electromagnetic waves? (2 points)
hjlf
What’s the answer choices to pick from?
4 0
3 years ago
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

C=\dfrac{8.85\times 10^{-12}\times 3.63^2\times 10^{-4}}{0.473\times 10^{-3}}

C=2.46 x 10⁻¹¹ F

U=\dfrac{1}{2}CV^2

V=Voltage difference

V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

7 0
3 years ago
Which fractures tend to occur first when a pane of glass is struck?
Irina18 [472]

Radial fractures tend to occur first when a pane of glass is struck.

Answer: Option A

<u>Explanation:</u>

There is a slight difference between radial and concentric fractures and as radial fractures are formed which extends outwards in a radial manner  from the point where the glass is struck.

Whereas concentric fractures are circular in pattern and they terminate long before radial crack. Also when a bullet is fired from a gun, a similar reaction is observed as it gets struck on the surface and fractures are formed in the same pattern.

4 0
3 years ago
WILL GIVE BRAINLIEST PLZ HELP REALLY URGENT
ozzi
D.) 5kg

This is a trick question. The mass of an object does not change based in location. However the weight of an object does change, this is because Weight = Mass × Gravity. Also mass is measured in kilograms and so the answer is 5 kg. So if you ever want to lose weight just go to the moon!
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3 years ago
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