1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nadezda [96]
3 years ago
14

George is applying a downward force of 50N to and object that has a mass of 50kg. What is the normal force (FN) of the object wh

ile George is applying the pressure?g=10 m/s2
Physics
1 answer:
attashe74 [19]3 years ago
3 0

The normal force acting on the object is 500 N in the upward direction

<u>Explanation:</u>

As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.

So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.

Normal\ force = Mass \times Acceleration\ due\ to\ gravity

Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then

Normal force = 50 × (-10) = -500 N

So, the normal force acting on the object is 500 N in the upward direction.

You might be interested in
Sheila uses a 45N force on her bowling ball across a 15m lane. What work did she do on the bowling ball? Show your work.​
Maurinko [17]

Answer:

675J

Explanation:

Given parameters:

Force  = 45N

Distance  = 15m

Unknown:

Work done by Sheila  = ?

Solution:

Work done by a body is the amount of force applied to make a body move through a distance;

         Work done  = Force x distance

 Now;

          Work done  = 45 x 15  = 675J

6 0
2 years ago
Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
s2008m [1.1K]

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: \frac{∆v}{t}

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 \frac{feet}{second} then sped up to 5 \frac{feet}{second}, then the change in my speed would be 2 \frac{feet}{second}, because I started walking 2 \frac{feet}{second} faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 \frac{meters}{second} to 16 \frac{meters}{second}  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = \frac{∆v}{t}

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 \frac{meters}{second} by 4 \frac{meters}{second}. That makes sense, right? Back to the equation.

a = \frac{∆v}{t}
a = \frac{16-4}{4}

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = \frac{12}{4}

a = 3 (\frac{meters}{second^{2}})

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit \frac{\frac{meters}{second}}{second}, which can be simplified down to \frac{meters}{second^{2} })

Let me know if you need clarification on anything I explained here!
- breezyツ

6 0
2 years ago
Is 5g greater than 20.43 mg
worty [1.4K]

yes that's true 6g is larger

4 0
3 years ago
Read 2 more answers
An object has a forward force of 100N and a reverse force of 25N. What is the resultant force?
iragen [17]

<u>Given</u><u>:</u>

  • An object has a forward force = 100N

  • An object has a reverse force = 25N

<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>

What is the resultant force?

<u>Solution</u><u>:</u>

Resultant Force = Forward force + Reserve force

= 100 N + ( - 25 N )

= 75 N

4 0
3 years ago
Read 2 more answers
The period and freqency of a wave are inversely related true or false​
Soloha48 [4]

Answer: false

Explanation: the longer the period, the less thef= frequency

5 0
3 years ago
Read 2 more answers
Other questions:
  • A particle moves along the x axis. It is intially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration -0.32
    8·1 answer
  • 1ST ANSWER WILL BE BRAINLIEST
    13·2 answers
  • Light year is a unit of?
    8·1 answer
  • 7. A wrench falls from a helicopter that is rising steadily at +6.0 m/s.
    10·1 answer
  • Zeros between a decimal point and a non-zero number are <br> (blank) significant
    10·1 answer
  • To determine an epicentral distance scientists consider the arrival times of what wave types
    8·1 answer
  • What’s Chemical energy
    13·2 answers
  • Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
    7·1 answer
  • Help on #2 will give brainliest and 40 points
    15·1 answer
  • What is the Frequency of a light wave with a Wavelength of 680 x 10^-7m?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!