Quarks are thought to be the basic component of what?

2 answers:

8 0

There are thought to be a few elementary particles which can't be broken down any further and these are mainly Quarks, Leptons and Gauge Bosuns.

Of course it may just mean that our equipment isn't advanced enough yet to further break these particles apart but at present we are fairly confident that these are true elementary particles.

there's the Gauge Boson. This is basically the means of transmitting the energy that comes from the four forces - for example the actual method by which a magnet exerts an attractive force on a drawing pin or whatever is thought to be by an exchange of massless, virtual particles. In the case of the magnet that would be the gauge boson that relates to electromagnetism, the photon.

vladimir2022 [97]3 years ago

5 0

Quarks are thought to be the basic component of protons and newtons.

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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.245 T. If the kinetic energy of the electr

Amiraneli [1.4K]

Answer

Given,

Magnetic field, B = 0.245 T

KE of the electron = 2.90 x 10⁻¹⁹ J

Speed of electron = ?

$KE = \dfrac{mv^2}{2}$

$v=\sqrt{\dfrac{2(KE)}{m}}$

$v=\sqrt{\dfrac{2\times 2.90\times 10^{-19}}{9.11\times 10^{-31}}}$

v = 7.97 x 10⁵ m/s

radius of the circular path

so,

$\dfrac{mv^2}{r}=evB$

$r=\dfrac{mv}{eB}$

$r=\dfrac{9.11\times 10^{-31}\times 7.97 \times 10^5}{1.6\times 10^{-19}\times 0.245}$

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8 0

3 years ago

If two variables have a non-related relationship and one of the variables is changed, how will the other variable change?

PolarNik [594]

If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.

None of the choices says this.

6 0

3 years ago

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$