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Effectus [21]
3 years ago
5

Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

Physics
1 answer:
Simora [160]3 years ago
7 0

Answer:

Electric flux will be \Phi =\frac{q}{\epsilon _0}

Explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to \frac{1}{\epsilon _0} times of charged enclosed by the surface.

So electric flux will be \Phi =\frac{q}{\epsilon _0}

Gauss law is only valid for closed surface it is not applied for open surface

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6 0
3 years ago
A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

8 0
3 years ago
If you pour different liquids into a graduated cylinder, which layer would be at the bottom?
klasskru [66]

the one that is more dense!

5 0
3 years ago
Convert 68852 millijoules into Calories. (Write your answer in the decimal form. Do not include units in your answer).
alex41 [277]

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories

6 0
3 years ago
An object on the surface of the earth has a force of gravity of 682 N. What is the objects mass?
valina [46]
The object's mass is around 69.592 kg

F=mg
5 0
3 years ago
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