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3 years ago

Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

Physics

1 answer:

Simora [160]3 years ago

7 0

Answer:

Electric flux will be $\Phi =\frac{q}{\epsilon _0}$

Explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to $\frac{1}{\epsilon _0}$ times of charged enclosed by the surface.

So electric flux will be $\Phi =\frac{q}{\epsilon _0}$

Gauss law is only valid for closed surface it is not applied for open surface

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A plane has an airspeed of 142 m/s. A 30.0 m/s wind is blowing southward at the same time as the plane is flying. What must be t

const2013 [10]

Answer:

$\theta=12.19^{\circ}$

Explanation:

Given that

The speed of the airplane ,v= 142 m/s

The speed of the air ,u = 30 m/s

Lets take angle make by airplane from east direction towards north direction is θ .

Now by using diagram ,we can say that

$sin\theta =\dfrac{u}{v}$

Now by putting the values in the above equation we get

$sin\theta =\dfrac{30}{142}$

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Therefore the angle will be 12.19° .

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3 years ago

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miss Akunina [59]

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2 years ago

I need help

Gala2k [10]

The energy of the wave will decrease.

The energy of a wave is given as

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3 years ago

Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of t

dsp73

Answer:

With the help of formula.

Explanation:

We can calculate the electric potential of any point through the formula of electric potential which is given below.

Electric potential = Coulomb constant x charge/ distance of separation.

Symbolically it can be written as, V = k q/ r where

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k = Coulomb constant

q = charge

r = distance of separation

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2 years ago