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3 years ago

Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

Physics

1 answer:

Simora [160]3 years ago

7 0

Answer:

Electric flux will be $\Phi =\frac{q}{\epsilon _0}$

Explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to $\frac{1}{\epsilon _0}$ times of charged enclosed by the surface.

So electric flux will be $\Phi =\frac{q}{\epsilon _0}$

Gauss law is only valid for closed surface it is not applied for open surface

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3 years ago

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2 years ago

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3 years ago

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2 years ago

Read 2 more answers

A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo

Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

$E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2$

$E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2$

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

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3 years ago