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Effectus [21]
3 years ago
5

Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

Physics
1 answer:
Simora [160]3 years ago
7 0

Answer:

Electric flux will be \Phi =\frac{q}{\epsilon _0}

Explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to \frac{1}{\epsilon _0} times of charged enclosed by the surface.

So electric flux will be \Phi =\frac{q}{\epsilon _0}

Gauss law is only valid for closed surface it is not applied for open surface

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Which electromagnetic waves have the shortest wavelengths and highest frequencies?
Usimov [2.4K]

Answer: Gamma rays

Explanation: The given waves belong to the electromagnetic spectrum which consists of different electromagnetic radiations arranged in terms of increasing wavelengths or decreasing frequencies.

E= h\times \nu

\nu=\frac{c}{\lambda}

Thus E=\frac{h\times c}{\lambda}

E= energy

\nu= frequency

c = speed of light

\lambda = wavelength

Thus frequency and wavelength are inversely related. The waves having high energies ave high frequencies and have shorter wavelengths.

Thus gamma rays having highest energy have highest frequency and shortest wavelength.


3 0
3 years ago
Read 2 more answers
Flying against the wind, an airplane travels 2670 km in 3 hours. Flying with the wind, the same plane travels 11,070 km in 9 hou
xxMikexx [17]

Answer:

speed of plane in still air = 1060 km/h

speed of wind = 170 km/h

Explanation:

Let teh speed of plane in still air is vp and the speed of air is va.

Irt travels 2670 km in 3 hours against the wind

So,

vp - va = 2670 / 3 = 890 km/h ..... (1)

It travels 11070 km in 9 hours along the wind.

vp + va = 11070 / 9 = 1230 km/h .... (2)

Adding both the equations

2 vp = 2120

vp = 1060 km/h

and va = 1230 - vp = 1230 - 1060 = 170 km/h

5 0
3 years ago
The blank is the core of an atom​
alexdok [17]

Answer:

The <u>nucleus</u> is the core of an atom.

Step-by-step explanation:

That's just how it is.

5 0
3 years ago
What do butterflies have on their feet which allows them to sense different strengths and types of nectar?
Andru [333]

The answer is D for sure.

4 0
3 years ago
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The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente
Gennadij [26K]

Answer:

18.1 × 10⁻⁶ A = 18.1 μA

Explanation:

The current I in the wire is I = ∫∫J(r)rdrdθ

Since J(r) = Br, in the cylindrical wire. With width of 10.0 μm, dr = 10.0 μm. r = 1.20 mm. We have a differential current dI. We integrate first by integrating dθ from θ = 0 to θ = 2π.

So, dI = J(r)rdrdθ

dI/dr = ∫J(r)rdθ = ∫Br²dθ = Br²∫dθ = 2πBr²

Now I = (dI/dr)dr at r = 1.20 mm = 1.20 × 10⁻³ m and dr = 10.0 μm = 0.010 mm = 0.010 × 10⁻³ m

I = (2πBr²)dr = 2π × 2.00 × 10⁵ A/m³ × (1.20 × 10⁻³ m)² × 0.010 × 10⁻³ m  =  0.181 × 10⁻⁴ A = 18.1 × 10⁻⁶ A = 18.1 μA

3 0
3 years ago
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