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Effectus [21]
3 years ago
5

Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

Physics
1 answer:
Simora [160]3 years ago
7 0

Answer:

Electric flux will be \Phi =\frac{q}{\epsilon _0}

Explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to \frac{1}{\epsilon _0} times of charged enclosed by the surface.

So electric flux will be \Phi =\frac{q}{\epsilon _0}

Gauss law is only valid for closed surface it is not applied for open surface

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