Answer:
c. alkyne.
Explanation:
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In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.
In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.
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Answer:
Explanation:
Mg²⁺ is divalent , hence
Molecular weight / 2 = equivalent weight .
.25 moles = 2 x .25 equivalents = .5 equivalents .
Cl⁻ is monovalent so
molecular weight = equivalent weight
.50 mole = .50 equivalent
Total equivalent = .50 of Mg²⁺ + .50 of Cl⁻
= 1 equivalent .
Answer:
8.08 × 10⁻⁴
Explanation:
Let's consider the following reaction.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
The initial concentration of phosgene is:
M = 2.00 mol / 1.00 L = 2.00 M
We can find the final concentrations using an ICE chart.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
I 2.00 0 0
C -x +x +x
E 2.00 -x x x
The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.
The concentrations at equilibrium are:
[COCl₂] = 2.00 -x = 1.96 M
[CO] = [Cl₂] = 0.0398 M
The equilibrium constant (Keq) is:
Keq = [CO].[Cl₂]/[COCl₂]
Keq = (0.0398)²/1.96
Keq = 8.08 × 10⁻⁴
Answer:
Cl
Explanation:
chlorine (2,8,7) is a non metal with highest electronegativity. Hence, it is most likely to form a negative ion with charge −1.
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