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KIM [24]
3 years ago
9

n atom “likes” to obtain a full outer shell. The fourth shell (in the atoms that we are studying today) can hold a maximum of 8

electrons. Think: Energetically, would the atom above “prefer” to give away its valence electrons or borrow some from another atom in order to fill its outer shell? Explain your reasoning
Chemistry
1 answer:
fgiga [73]3 years ago
4 0

It depends on how many electrons are already in the outer shell.

If it is a large amount (if it is almost to the maximum), then it will want to borrow from another atom.

But if it is close to empty then it will want to give away so it will go back to the inner ring with will be full.

Hope this helps, good luck!

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Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].

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Equilibrium constant=[concentration of products]/[concentration of reactants]

The concentration of reactant  molecules is maximum at time 0 and it  decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.

All the changes would occur in accordance with the LeChateliers principle.

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a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.

b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature  the reaction would shift forwards as  more heat energy is absorbed by reactants  to form more products.

c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.

d Since  this reaction is endothermic in nature so when we remove the heat from reaction hence even less amount of heat is present in the system and so the reaction shift in backward direction as the reaction cannot proceed without enough amount of heat.

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