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NemiM [27]
3 years ago
6

An object’s resistance to change in motion is dependent solely on what quantity

Physics
1 answer:
Levart [38]3 years ago
4 0

That's the description of the property of so-called "inertia".

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A communications channel has a bandwidth of 4,000 hz and a signal-to-noise ratio (snr of 30 db. what is the maximum possible dat
levacccp [35]
Through Shannon's Theorem, we can calculate the capacity of the communications channel using the value of its bandwidth and signal-to-noise ratio. The capacity, C, can be expressed as 

C = B × log₂(1 + S/N)

where B is the bandwidth of the channel and S/N is its signal-to-noise ratio.

Since the given SN ratio is in decibels, we must first express it as a ratio with no units as

SN (in decibels) = 10 × log (S/N)
30 = 10log(S/N)
log(S/N) = 3
S/N = 10³ = 1000

Now that we have S/N, we can solve for its capacity (in bits per second) as 

C = 4000 × log₂(1 + 1000) 
C = 39868.91 bps

Thus, the maximum capacity of the channel is 39868 bps or 40 kbps.

Answer: 40 kbps

 
4 0
3 years ago
A small ball with mass 2.50 kg is mounted on one end of a rod 0.750 m long and of negligible mass. The system rotates in a horiz
alina1380 [7]

Answer:

1.40625 kg-m^2

Explanation:

Supposing we have to calculate rotational moment of inertia

Given:

Mass of the ball m= 2.50 kg

Length of the rod, L= 0.78 m

The system rotates in a horizontal circle about the other end of the rod

The constant angular velocity of the system, ω= 5010 rev/min

The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less

I_{sys}= mL^2= 2.50\times 0.75^2

=1.40625 kg-m^2

m= mass of the ball and L= length of the ball

3 0
3 years ago
Two massive objects are fixed in position. A third object is placed directly between the first two at the position at which the
ivanzaharov [21]

Answer:

Explanation:

Be M1 and M2 the two massive objects and m the third one

The gravitational force over the third object at the beginning is zero (assuming that the position of the third object is x=0)

F_{m}=-G\frac{mM_{1}}{x_{1}^{2}}-G\frac{mM_{2}}{x_{2}^{2}}=0

when the third object is displaced we have that the new position is x=Δx. Hence

F_{m}=-G\frac{mM_{1}}{(-x_{1}+\Delta x)^{2}}-G\frac{mM_{2}}{(x_{2}-\Delta x)^{2}}

I attached a scheme of the system

I hope this is useful for you

Regards

5 0
3 years ago
A physicist makes a cup of instant coffee and notices that, as the coffee cools, its level drops 3.00 mm in the glass cup. Show
motikmotik

Answer:

Decrease in level by thermal contraction  = 0.0076 mm

Drops in level = 3 mm

Therefore The decrease in level is not due to thermal contraction

Explanation:

From linear expansivity,

L₂ = L₁ +(1 + αΔT).............................. equation 1

Where L₂ = final length (m), L₁ = initial length, α = linear expansivity of liquid, ΔT = change in temperature.

Where L₁ = level of coffee in the glass cup = V/(πd²)/4..................... equation 2

     L₁ = 4V/πd², where V= Volume of coffee, d = diameter of the cup,

    L₁ = 350cm³, d = 7.00cm, and    π = 22/7 = 3.143

applying these values in equation 2 above,

     ∴  L ₁=( 4×350)/(3.143×7²)

       L₁ = 9.09

α = γ/3  Where γ = Volumetric expansion coefficient of liquid. = 0.00005/°C

α = 0.00005/3 = 0.0000167/°C, ΔT = L₂ - L₁ = 45 -95 = -50 °C.

Applying these values in equation 1 above,

L₂ = 9.09 [1+{0.0000167×(-50)}]

L₂ = 9.09 [1 - 0.000833]

L₂ = 9.09(0.999167)

L₂ = 9.082cm

∴ ΔL = Decrease in length = L₂ - L₁ = 9.082 - 9.09 = 0.3 cm

   ΔL = 0.0076

Decrease in level =0.076 mm

From the above, the decrease in level is not due to thermal contraction.

As Thermal contraction is less than Drops in level.

4 0
3 years ago
15. Two like charges: A. Attract each other B. Repel each other C. Must be neutrons D. Neutralize each other
seropon [69]

Answer:

B. Repel each other

Explanation:

Two like charges have the same sign. Example an electron with a negative charge (-e) and another electron with same charge(-e). Or a proton with a positive charge (+e) and another proton with same charge (+e). Since each of  these pair charges have the same sign, they will repel each other.

On the other hand, if the charges are opposite, ie  negative charge and positive charge, they will attract each other.

B. Repel each other

7 0
3 years ago
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