The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:
FΔx = 0.5mv²
F = force, Δx = distance traveled, m = mass, v = speed
Isolate Δx:
Δx = 0.5mv²/F
Calculate Δx for each object.
Object 1: m = 4.0kg, v = 2.0m/s
Δx = 0.5(4.0)(2.0)²/F = 8/F
Object 2: m = 1.0kg, v = 4.0m/s
Δx = 0.5(1.0)(4.0)²/F = 8/F
The two objects travel the same distance before stopping.
Answer:
Inside a femur bone found in the woods,
saliva of gum
Pretty sure its.false if its.wrong
Sorry still. Having issues myself. hope.its right
Answer:
restoring force is 2 N
Explanation:
given data
angle pulled = 5°
force = 1 N
pulled = 10°
to find out
restoring force
solution
we know here force
force = m×g×sinθ ..........1
so here θ is very small so sinθ = θ
1 = mg(5)
mg = 1 /5 ..................2
and
now for 10 degree
we know here θ is small so sinθ = θ
so from equation 1
force = m×g×sinθ
put equation 2 here
force = 1/5 × 10
force = 2 N
so restoring force is 2 N