Answer:
at t=46/22, x=24 699/1210 ≈ 24.56m
Explanation:
The general equation for location is:
x(t) = x₀ + v₀·t + 1/2 a·t²
Where:
x(t) is the location at time t. Let's say this is the height above the base of the cliff.
x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0
v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.
a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².
Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.
Ball: x(t) = 46.0 + 0 - 1/2*9.8 t²
Stone: x(t) = 0 + 22·t - 1/2*9.8 t²
Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:
46 = 22·t
so t = 46/22 ≈ 2.09
Put this t back into either original (i.e., with the quadratic term) equation and get:
x(46/22) = 46 - 1/2 * 9.806 * (46/22)² ≈ 24.56 m
To find the average (aka mean) of a group of numbers, all we need to do is add them up then divide that number by how many numbers we started with
23 + 21 + 24 + 22 = 90
90 ÷ 4 = 22.5
Therefore, the average distance the book traveled on ice is 22.5 cm
15 + 18 + 16 + 17 = 66
66 ÷ 4 = 16.5
Therefore, the average distance the book traveled on concrete is 16.5 cm
In conclusion, the average distance the book traveled on ice is greater than the average distance the book traveled on concrete
Hope this helps you
-AaronWiseIsBae
Answer:
Planet, in which he concluded that Planet X had a mass roughly seven times that of Earth—about half that of Neptune—and a mean distance from the Sun of 43 AU. He assumed Planet X would be a large, low-density object with a high albedo, like the giant planets
Explanation:
Ek= 1/2mv²
200=1/2 m(9 ²)
200=1/2(81)m
200=40.5m
m=200/40.5
m=4.93kg
Answer: 4.9 kg (second option)
The potential energy of the ball before it falls is (mass) (gravity) (height) =
(0.5 kg) (9.8 m/s²) (4 m) = 19.6 joules
The kinetic energy of the ball when it hits the ground is (1/2) (mass) (speed)² =
(1/2) (0.5 kg) (5 m/s)² = (0.25 kg) (25 m²/s²) = 6.25 joules
a). The <em>energy lost</em> to air resistance during the fall is (19.6J - 6.25J) = <em>13.35 Joules. </em><em>Energy is never destroyed, so these missing joules had to go somewhere. This is the </em><em>work done on the ball by air resistance</em><em> during the fall of the ball.</em>
b). Air resistance worked on the ball all during the fall of 4 meters.
Work = (force) x (distance)
13.35 Joules = (force) x (4 meters)
Divide each side by (4 meters) :
Average force = (13.35 Joules / 4 meters)
<em>Average force = 3.3375 Newtons</em>