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3 years ago

How would you classify sugar?

Chemistry

2 answers:

diamong [38]3 years ago

6 0

Answer: A. Pure substance - compound

Explanation: Sugars or sacharrides are complex compounds having Carbon,Hydrogen and Oxygen atoms on its composition. Since a combination of two or more different elements forms a compound and compounds are pure substances.

Aleonysh [2.5K]3 years ago

4 0

Answer:

The answer to your question is a) pure substance- compound

Explanation:

a) pure substance-compound. A pure substance can be an element or compound that is not mixed with another substance, glucose is a compound and also a pure substance.

b) mixture-heterogeneous. This option is wrong because glucose is not mixed with another substance.

c) pure substance-element. Glucose is a pure substance but it is a compound because it is composed of carbon, hydrogen, and oxygen. This option is incorrect.

d) mixture-homogeneous. Glucose is not a mixture, it is a pure substance. This option is wrong.

e) none of the above. This option is wrong because the first option is correct.

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How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

Nina [5.8K]

11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=298 K

Putting value in the given equation:

$\frac{PV}{RT}=n$

$n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}$

Moles = 0.3588 moles

Now,

$Moles = \frac{mass}{molar \;mass}$

$0.3588 moles = \frac{mass}{32}$

Mass= 11.48 gram

Hence, 11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

Learn more about the ideal gas here:

brainly.com/question/27691721

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3 0

2 years ago

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential

nika2105 [10]

Answer:

3.50*10^-11 mol3 dm-9

Explanation:

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.

Ag2C2O4 --> 2Ag+ + C2O4 2-

So Ksp = [Ag+]^2 * [C2O42-]

In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.

So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)

= 3.50*10^-11 mol3 dm-9

7 0

3 years ago

Cuanto se demora un clavo en un envase con vinagre en oxidarse?

Alexxandr [17]

Answer:

Verter lentamente partes iguales de vinagre y peróxido de hidrógeno para formar la solución. Mezclar estos dos ingredientes crea una pequeña cantidad de ácido peracético que oxidará el metal en la uña y creará óxido. La solución debe empezar a inflamarse y ponerse roja en los próximos cinco minutos.

Explanation:

6 0

3 years ago

How many molecules in 4.10 mol H2O?

Shtirlitz [24]

Answer:

2,47 * $10^{24}$ (molecules)