Answer:
U=4m/s
V=6m/s
T=5s
Acceleration =v-u/t
6-4/5
=2/5 metre/second(square).
2.71 m/s fast Hans is moving after the collision.
<u>Explanation</u>:
Given that,
Mass of Jeremy is 120 kg (
)
Speed of Jeremy is 3 m/s (
)
Speed of Jeremy after collision is (
) -2.5 m/s
Mass of Hans is 140 kg (
)
Speed of Hans is -2 m/s (
)
Speed of Hans after collision is (
)
Linear momentum is defined as “mass time’s speed of the vehicle”. Linear momentum before the collision of Jeremy and Hans is
= ![=\mathrm{M}_{1} \times \mathrm{V}_{\mathrm{J}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{H}}](https://tex.z-dn.net/?f=%3D%5Cmathrm%7BM%7D_%7B1%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BJ%7D%7D%2B%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BH%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BH%7D%7D)
Substitute the given values,
= 120 × 3 + 140 × (-2)
= 360 + (-280)
= 80 kg m/s
Linear momentum after the collision of Jeremy and Hans is
= ![=\mathrm{M}_{\mathrm{J}} \times \mathrm{V}_{\mathrm{JA}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{HA}}](https://tex.z-dn.net/?f=%3D%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BJ%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BJA%7D%7D%2B%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BH%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BHA%7D%7D)
= 120 × (-2.5) + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
= -300 + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
We know that conservation of liner momentum,
Linear momentum before the collision = Linear momentum after the collision
80 = -300 + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
80 + 300 = 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
380 = 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
380/140= ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
= 2.71 m/s
2.71 m/s fast Hans is moving after the collision.
Answer:
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion. It is the basic force responsible for such effects as the action of electric motors and the attraction of magnets for iron. Electric forces exist among stationary electric charges; both electric and magnetic forces exist among moving electric charges. The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.
Answer:
Inductance, L = 0.0212 Henries
Explanation:
It is given that,
Number of turns, N = 17
Current through the coil, I = 4 A
The total flux enclosed by the one turn of the coil, ![\phi=5\times 10^{-3}\ Tm^2](https://tex.z-dn.net/?f=%5Cphi%3D5%5Ctimes%2010%5E%7B-3%7D%5C%20Tm%5E2)
The relation between the self inductance and the magnetic flux is given by :
![L=\dfrac{N\phi}{I}](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7BN%5Cphi%7D%7BI%7D)
![L=\dfrac{17\times 5\times 10^{-3}}{4}](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7B17%5Ctimes%205%5Ctimes%2010%5E%7B-3%7D%7D%7B4%7D)
L = 0.0212 Henries
So, the inductance of the coil is 0.0212 Henries. Hence, this is the required solution.
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