Answer:
I=V/R
Explanation:
Ohm's law gives the mathematical relationship between, current, voltage and the resistance of the circuit. Its mathematical form is given by :
V = IR ....(1)
V = voltage (in volts)
I = current (in Ampere)
R = resistance (in ohms)
Equation (1) can be rewritten as :
Hence, the correct relation is I=V/R.
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values,
v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.
This took me a short while to figure out, but I am still not entirely sure if this is correct, this is just from my basic understanding of Newtons Second Law of Motion.
You have a 4kg cart with a force of 20N acting on it.
The formula for working out the acceleration is.
a=Fnet÷mass
Substitute in the information.
a=20N÷4kg
Now you solve it to give you.
a=5m/s
So now what you should be able to do is figure out that after 10 seconds the cart travelling at 5m/s would have travelled 10 metres.
This is achieved by finding out how many 5's go into 10 which is 2.
So you do 5×2 which equals 10.
The 4kg cart has travelled 10 meters in 10 seconds with a force of 20N acting upon it.
I hope that this has helped you.
Answer:
0.67 m/s
Explanation:
Mass of car 1, m₁ = 5000 kg
Mass of car 2, m₂ = 10,000 kg
Initial speed of car 1, u₁ = 2 m/s
Final speed of car 2, u₂ = 0 (at rest)
We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.
So, after the inelastic collision, they will move with a speed of 0.67 m/s.
