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faltersainse [42]
3 years ago
7

Which statement describes an intensive property of matter

Physics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

where are the statements so i can see which one is correct

Explanation:

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An athlete on a sled is moving with a speed of 3.0 m/s across a pond covered with ice. If the total mass of the sled-athlete sys
enot [183]

Given Information:

Mass = m = 95 kg

Initial velocity = v₁ = 0 m/s

Final velocity = v₂ = 3 m/s

time = t = 15 seconds

Required Information:

magnitude of average force = ?

Answer:

magnitude of average force = 19 N

Explanation:

From the Newton's second law of motion

F = ma

From the kinematics equations,

v₂ = v₁ + at

at = v₂ - v₁

a = (v₂ - v₁)/t

a = (3 - 0)/15

a = 0.2 m/s²

F = 95*0.2

F = 19 N

Therefore, the magnitude of the average force required to bring the sled to rest is 19 N.

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3 years ago
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What will happen if an object or liquid with a density less than 1.0 g/cm3 is placed into water; do the same for an object or li
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If the object has a lower density than water, it will float.

If the object has a higher density than water, it will sink.
3 0
3 years ago
What is the net work on the block?
Strike441 [17]

Answer:

A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size

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3 years ago
Pls pls help me out AHH, what is not true about MEIOSIS?
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Answer:

B.

Explanation:

This is not true as the number of chromosomes in the daughter cells are half the number in the parent's cells

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8. Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of outp
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The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

  • Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

  • Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

#SP1

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2 years ago
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