Explanation:
<em>an </em><em>eclipse </em><em>happens </em><em>when </em><em>one </em>
<em>astronomical </em><em>body </em><em>block </em><em>light </em>
<em>from </em><em>or </em><em>to </em><em>another</em><em>,</em><em> </em><em>the </em><em>moon </em><em>moves </em><em>into</em>
<em>the </em><em>shadow </em><em>of </em><em>earth </em><em>cast </em><em>by </em><em>sun</em><em>.</em><em>.</em><em>.</em><em> </em><em>In </em><em>a </em><em>solar </em>
<em>eclipse</em><em>,</em><em> </em><em>the </em><em>moon </em><em>passes </em><em>between </em><em>Earth </em>
<em>and </em><em>the </em><em>sun </em><em>stops </em><em>some </em><em>all </em><em>of </em><em>the </em><em>sun's </em><em>light</em>
<em>from </em><em>reaching </em><em>Earth </em>
Answer:
1350N
Explanation:
The force exerted on the hand would be the momentum divided by the duration of contact.
As the hand is coming to rest, final velocity would be 0
The magnitude of the force would be 1350N
Answer:
'Incident rays that are parallel to the central axis are sent through a point on the near side of the mirror'.
Explanation:
The question is incomplete, find the complete question in the comment section.
Concave mirrors is an example of a curved mirror. The outer surface of a concave mirror is always coated. On the concave mirror, we have what is called the central axis or principal axis which is a line cutting through the center of the mirror. The points located on this axis are the Pole, the principal focus and the centre of curvature. <em>The focus point is close to the curved mirror than the centre of curvature.</em>
<em></em>
During the formation of images, one of the incident rays (rays striking the plane surface) coming from the object and parallel to the principal axis, converges at the focus point after reflection because all incident rays striking the surface are meant to reflect out. <em>All incident light striking the surface all converges at a point on the central axis known as the focus.</em>
Based on the explanation above, it can be concluded that 'Incident rays that are parallel to the central axis are sent through a point on the near side of the mirror'.
The answer is kinetic energy
