Answer:
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- <u><em>pOH = 0.36</em></u>
Explanation:
Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.
<u>1. Potassium hydroxide solution, KOH</u>
- Volume, V = 304 mL = 0.304 liter
- number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
- 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944
<u>2. LIthium hydroxide, LiOH</u>
- Volume, V = 341 mL = 0.341 liter
- number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
- 1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391
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<u>3. Resulting solution</u>
- Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol
- Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter
- Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M
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<u>4. </u><em><u>pOH</u></em>
← answer
Answer:
A) 0.801
Explanation:
The reaction that takes place is:
- 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
First we c<u>alculate the H₂SO₄ moles that reacted</u>:
- 0.355 M * 28.2 mL = 10.011 mmol H₂SO₄
Now we <u>convert H₂SO₄ moles to NaOH moles</u>:
- 10.011 mmol H₂SO₄ *
= 20.022 mmol NaOH
Finally we <u>calculate the molarity of the NaOH solution</u>:
- 20.022 mmol NaOH / 25.0 mL = 0.801 M
So the answer is option A.
A chemical property of soda ash is that it is an alkaline compound , of pH 11.6 in aqueous solution. The chemical name of soda ash is sodium carbonate. It is a sodium salt of carbonic acid and occurs as a white crystalline compound. It has a cooling alkaline taste. It can be found in the ashes of many plants. It is produced in large quantities from sodium chloride (common salt). It can be found as a mineral in mineral deposits of natron usually in seasonal lakes when the lakes dry up.
Answer:
The piece of wood will sink
Explanation:
If an object has a density higher than water, it will sink, and the piece of wood is more dense than water when measured.
Answer: 234.4K
Explanation:
Given that,
Original volume of gas (V1) = 5.00 L
Original temperature of gas (T1) = 20.0°C
[Convert 20.0°C to Kelvin by adding 273
20.0°C + 273 = 293K]
New volume of gas (V2) = 4.0L
New temperature of gas (T2) = ?
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
5.00L/293K = 4.0L/T2
To get the value of T2, cross multiply
5.00L x T2 = 293K x 4.0L
5.00L•T2 = 1172L•K
Divide both sides by 5.00L
5.00L•T2/5.00L = 1172L•K/5.00L
T2 = 234.4K
Thus, the new temperature of the gas is 234.4 Kelvin