Answer:
Q = 2.60 •
J
Explanation:
Our specific heat capacity equation is:
Q = mC∆T
Q is the energy in joules.
m is the mass of the substance.
∆T is the temperature chance.
Let's plug in what we know.
- We have 76.0 g of octane
- The specific heat capacity of octane is 2.22 J/(g•K)
- The temperature increases from 10.6º to 26.0º (a 15.4º increase)
Q = 76.0(2.22)(15.4)
Multiply.
Q = 2598.288
We want three significant figures.
Q = 2.60 • 
or
Q = 2590 J
Hope this helps!
It is hard because we can't get past the crust, Our machines will burn up at the mantle and so will we. The layers go: crust, mantle, outer core, inner core.
Answer:
25.2°C
Explanation:
Given parameters:
Energy applied to the water = 1000J
Mass of water = 50g
Final temperature = 30°C
Unknown:
Initial temperature = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the energy absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
1000 = 50 x 4.184 x (30 - initial temperature )
1000 = 209.2(30 - initial temperature)
4.78 = 30 - initial temperature
4.78 - 30 = - initial temperature
Initial temperature = 25.2°C
Sodium/Atomic number
11
Gold/Atomic number
79
Potassium/Atomic number
19
Silicon/Atomic number
14
Answer:
The answer you selected is correct (A)have
Explanation:
Red blood cells one goal which is to carry oxygen throughtout your body.. without it you would die to lack of oxygen.