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Sever21 [200]
3 years ago
14

Water is a very unique substance because it can exist in all three phases of matter (solid, liquid, gas) within the normal tempe

rature ranges found on Earth.
When one observes the phase of matter of water, one observes a ________ property of matter.
Physics
2 answers:
vredina [299]3 years ago
7 0
Qualitative is the answer
ahrayia [7]3 years ago
5 0
 the answer is qualitative
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Determine the momentum of a 15,000 kg truck traveling at 15 m/s
S_A_V [24]

Answer:

mass*velocity=1.5*10^4 * 15

= 22.5*10^4

6 0
3 years ago
A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces t
Katyanochek1 [597]
By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
6 0
3 years ago
can someone help me answer this? i dont get it and I need help before the next 30 minutes. ill give a brainiest to whoever helps
Zinaida [17]

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

3 0
4 years ago
How much potential energy does a 20-kg barrel have when it is in the truck whose floor is 5.0 m above the ground? P.E. = J
MrRa [10]
The answer is 980 J.
6 0
3 years ago
Read 2 more answers
point) A tank in the shape of an inverted right circular cone has height 5 meters and radius 4 meters. It is filled with 4 meter
zysi [14]

Answer:

W = 907963.50 J = 907.96 J

Explanation:

Note: Refer to the figure attached

Now, from the figure we have similar triangles ΔAOB and ΔCOD

we have

\frac{5}{4}=\frac{x}{r}

or

r=\frac{4x}{5}

Now, the work done to empty the tank can be given as:

W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx

or

W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx

or

W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx

or

W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx

or

W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0

or

W = 6773.76\pi[\frac{128}{3}]

or

W = 907963.50 J = 907.96 J

7 0
3 years ago
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