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dimulka [17.4K]
2 years ago
15

Where an electric field line crosses an equipotential surface, the angle between the field line and the equipotential is

Physics
1 answer:
n200080 [17]2 years ago
4 0

Answer:

90 degree

Explanation:

Electric field line is vertical to the electric field line.

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A dragster starts with zero velocity and completes a 404.5 m (0.2528 mile) run in 4.922 s. If the car had a constant acceleratio
KIM [24]

Answer:

a. a=33.34ms⁻², V=164.4m/s

Explanation:

Since the dragster started with zero velocity, de determine the acceleration using of the equations of motion.

Below are the data given

Distance, s=404.5m,

time taken,t=4.922secs

Using the equation

S=ut+1/2at²

where u is the initial velocity and u=0

Making the acceleration the subject of the formula, we arrive at

a=2s/t²

a=(2*404.5)/4.922²

a=33.34ms⁻².

To determine the velocity, we use

V=u+at

V=0+33.34ms⁻² *4.922sec

V=164.4m/s

5 0
3 years ago
Read 2 more answers
calculate the resistance of 50m length of wire of cross sectional area 0.01 square mm and of resistivity 5*10 to the power minus
Pachacha [2.7K]
Resistance R = resistivity * length / area

R = 5  10^{-8} * 50 m / 0.01 *  10^{-3} * 10^{-3}

R =  250 Ohms

8 0
3 years ago
The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i
Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius=r=\frac{d}{2}=\frac{2.3}{2}=1.15 m

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency=\frac{1200}{60}=20 Hz

1 minute=60 seconds

Angular velocity=\omega=2\pi f

Angular velocity=2\times \frac{22}{7}\times 20=125.7 rad/s

b.We have to find the linear speed of its tip at this  angular velocity if the plane is stationary on the tarmac.

v=r\omega=1.15\times 125.7=144.56 m/s

c.Centripetal acceleration=\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2

Centripetal acceleration==\frac{18170.56\times g}{9.81}=1852.25 g m/s^2

7 0
3 years ago
Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the
ankoles [38]

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

  • Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
  • It resembles the way a ball bounces when we toss it on a hard surface.
  • Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
  • The given values are:Light from a monochromatic source,= 560 nm
  • The angle of incidence,= 60°
  • The surface of fused quartz (n),= 1.56
  • When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
  • According to the above law,Angle of incident = angle of reflection
  • Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

#SPJ4

7 0
1 year ago
At its natural resting length, a muscle is close to its optimallength for producing force. As the muscle contracts, the maximumf
lesantik [10]

Answer:

Figure E is the correct representation of the first part of the motion. When in a hanging position from the chin-up bar, the bicep muscles are stretched beyond their normal length already. So at this point they are at the peak of their capacity and you are at rest (this corresponds to the velocity v = 0 at t = 0). On contracting the bicep muscles and pulling your whole body up, you begin to gain speed and v increases. This increase in velocity is exponential. Soon the bicep muscles contract up to 80% their normal length reducing the force they can produce to keep you rising up to zero. The velocity change happens because the body is accelerating and the muscles can still supply a net force to lift you up. The acceleration is present because of this net force. The moment this force reduces to zero, the acceleration too reduces to zero. (From Newton's second law of motion). This reduction in acceleration is responsible for the reduction of the curvature of the v curve in figure E above. The point where the velocity becomes horizontal corresponds to the point where the muscles reach their maximum contraction unit and can supply no more net force and as a result no acceleration. This further results inba constant velocity which is the flat nature of the curve seen in diagram E.

Thank you for reading.

Explanation:

5 0
3 years ago
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