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3 years ago

Can somone pls help me??!! i’m very stuck

Physics

1 answer:

Alchen [17]3 years ago

3 0

Answer:

its the third one

Explanation:

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What provides most of the force to allow the runners to move?

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Answer:

When you are running the most important force that you should understand is friction. Friction is a force that opposes movement between two objects, but for runners friction makes you faster. Friction gives you a better and more efficient way to use your energy into speed.

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3 years ago

If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot

Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=I_{1}+I_{2}$

$I=(m+m_{1})\times r^2+(m+m_{2})\times r^2$

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

$I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2$

$I=117.45\ kg-m^2$

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

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3 years ago

Three resistors with the values of R_1, R_2, and R_3 are connected in parallel. Which of the following expresses the total resis

bagirrra123 [75]

Answer: Option d.)

R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Explanation:

Since, there are three resistors connected in parallel, the reciprocal of the total resistance of the resistor combination (R_eq) is obtained by adding the reciprocal of each resistance.

i.e 1/R_eq = (1/R_1 + 1/R_2 + 1/R_3)

So, R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Thus, the total resistance (R_eq) is equal to the inverse of the sum of the reciprocal of each resistance.

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4 years ago

A spring has a spring constant of 81 N · m−1. What is the force (in N) required to do the following? (Enter the magnitude.) (a)

DochEvi [55]

Explanation:

It is given that,

Spring constant, k = 81 N/m

We need to find the force required to :

(a) Compress the spring by 6 cm i.e. x₁ = 6 cm = -0.06 m

It can be calculated using Hooke's law as :

F = - k(-x₁)

$F=81\ N/m\times 0.06\ m$

F = 4.86 N

(b) Expand the spring by 17 cm i.e. x₂ = 17 cm = +0.17 m

So, F = -kx₂

$F=-81\ N/m\times 0.17\ m$

F = -13.77 N

Hence, this is the required solution.

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3 years ago

Which material is the LEAST dense?

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4 years ago

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