Answer:
flow ( m ) = 4.852 kg/s
Explanation:
Given:
- Inlet of Turbine
P_1 = 10 MPa
T_1 = 500 C
- Outlet of Turbine
P_2 = 10 KPa
x = 0.9
- Power output of Turbine W_out = 5 MW
Find:
Determine the mass ow rate required
Solution:
- Use steam Table A.4 to determine specific enthalpy for inlet conditions:
P_1 = 10 MPa
T_1 = 500 C ---------- > h_1 = 3375.1 KJ/kg
- Use steam Table A.6 to determine specific enthalpy for outlet conditions:
P_2 = 10 KPa -------------> h_f = 191.81 KJ/kg
x = 0.9 -------------> h_fg = 2392.1 KJ/kg
h_2 = h_f + x*h_fg
h_2 = 191.81 + 0.9*2392.1 = 2344.7 KJ/kg
- The work produced by the turbine W_out is given by first Law of thermodynamics:
W_out = flow(m) * ( h_1 - h_2 )
flow ( m ) = W_out / ( h_1 - h_2 )
- Plug in values:
flow ( m ) = 5*10^3 / ( 3375.1 - 2344.7 )
flow ( m ) = 4.852 kg/s
Answer:
0.2 kcal/mol is the value of 
for this reaction.
Explanation:
The formula used for is:
where,
= Gibbs free energy for the reaction
= standard Gibbs free energy
R =Universal gas constant
T = temperature
Q = reaction quotient
k = Equilibrium constant
We have :
Reaction quotient of the reaction = Q = 46
Equilibrium constant of reaction = K = 35
Temperature of reaction = T = 25°C = 25 + 273 K = 298 K
R = 1.987 cal/K mol
![=-1.987 cal/K mol\times 298 K\ln [35]+1.987 cal/K mol\times 298K\times \ln [46]](https://tex.z-dn.net/?f=%3D-1.987%20cal%2FK%20mol%5Ctimes%20298%20K%5Cln%20%5B35%5D%2B1.987%20cal%2FK%20mol%5Ctimes%20298K%5Ctimes%20%5Cln%20%5B46%5D)
1 cal = 0.001 kcal
0.2 kcal/mol is the value of for this reaction.
Answer:
No the sample mean is not the most frequently occurring data.
Explanation:
If we take a number of observation in an experiment the most frequently repeating value is known as mode of data.
Mean of data is the the value to which all the given observational values are closest.
Consider a given set of observations as
1,1,1,1,1,5,4,3,4
The Mean of the above data set is
While as the most often repeating value is 1 which is not equal to mean
Answer:
In C++:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double total = 0;
for(int i = -170; i<=-130;i++){
if(i%2 == 0 && i%7==0){
double angle = i*3.14159/180;
total+=sin(angle); } }
cout<<"Total: "<<total;
return 0;
}
Explanation:
This initializes the total to 0
double total = 0;
This iterates from -170 to - 130
for(int i = -170; i<=-130;i++){
This checks if the current number is even and is divided by 7
if(i%2 == 0 && i%7==0){
This converts the number from degrees to radians
double angle = i*3.14159/180;
This adds the sine of the number
total+=sin(angle); } }
This prints the calculated total
cout<<"Total: "<<total;
