load every electric circuit,regardless of where it is or how large or small, has four basic parts: an energy source (ac or dc),a conductor (wire), an electrical load (device), and at least one controller(switch)
Both A and B technicians are correct because both might be used to test fuses, according to technician B.
<h3>What is continuity?</h3>
The behavior of a function at a certain point or section is described by continuity. The limit can be used to determine continuity.
From the question:
We can conclude:
The technician claims that you may check for continuity using both an ohmmeter and a self-powered test light. Both might be used to test fuses, according to technician B.
Thus, both A and B technicians are correct because both might be used to test fuses, according to technician B.
Technician A says both an ohmmeter and a self-powered test light may be used to test for continuity. Technician B says both may be used to test fuses. Who is correct?
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Answer:
Option B
Explanation:
An operational amplifier usually has a high open loop gain of around 10^5 which allows a wide range get of feed back levels in order to achieve the desired performance so therefore a low open loop gain reduces the range feed back level thereby reducing the performance which can cause errors in the output voltage.
It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.
<h3>What is
Maclaurin Expansion?</h3>
The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!
<h3>
What is the explanation for the above?</h3>
as indicated above, the Maclaurin infinite series expansion is given as:
F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!
If F(0) = Cot 0
F(0) = ∝ = 1/0
This is not definitive,
Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.
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