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Alika [10]
1 year ago
14

Report accidents to your teacher,no matter how they may seem

Chemistry
1 answer:
allochka39001 [22]1 year ago
6 0

Answer:

I mean If you're asking a question, then yes.

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Isotopes are atoms of the same element with the same number of protons and a different number of
Neporo4naja [7]
<span>Isotopes are atoms of the same element with the same number of protons and a different number of:

</span><span>c. neutrons.</span>
5 0
3 years ago
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Write the complete electron configuration for an atom of element 3
kondaur [170]
Based on the ionization energy levels of element 3, one can tell that the element is Magnesium. Magnesium has an atomic number of 12 so in a neutral atom, that means that there are 12 protons and 12 electrons. So based on the electrons, we can write the electronic configuration as:

1s^{2}  2s^{2}  2p^{6}  3s^{2}
3 0
3 years ago
3.
LenKa [72]

Answer: 23 g

the mol of Fe is 11,5/56 = 23/112 (mol)

the mol of CO is \frac{2,63.10^{24} }{6.10^{23} }= \frac{263}{60} (mol)

we have:

Fe2O3 + 3CO => 2Fe + 3CO2

23/112    69/112     23/56

=> the mol of Fe is 23/56 mol

=> the mass of Fe is 23/56.56 = 23 (g)

Explanation:

4 0
2 years ago
What is the volume of 6.50g of gold if the density of gold is 19.3g/ml?
Jet001 [13]

Answer:

0.33 ml

Explanation:

Formula for density: p = m/V (where p is <em>density</em>, m is <em>mass</em> and V is <em>volume</em>)

So, by applying the above formula:

19.3 =  \frac{6.5}{v}

v = 0.33 \: ml

7 0
3 years ago
.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f
Tasya [4]

Answer : The value of K_c for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)

The expression of K_c will be,

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

First we have to calculate the concentration of Br_2,Cl_2\text{ and }BrCl.

\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M

Now we have to calculate the value of K_c for the given reaction.

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

K_c=\frac{(0.6)^2}{(1)\times (1)}

K_c=0.36

Therefore, the value of K_c for the given reaction is, 0.36

6 0
3 years ago
Read 2 more answers
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