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3 years ago

Draw a lewis structure for so2 in which all atoms obey the octet rule. show formal charges. do not consider ringed structures.

Chemistry

1 answer:

Aleonysh [2.5K]3 years ago

6 0

Formal charge = valence electron - bonds - dots.
double bonded oxygen = 6-2-
4 so it is 0
single bonded oxygen = 6-1-6 so it is -1
sulfur = 6-3-2 so it is +1

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Some kayakers coat the bottom of their kayaks with wax to make them more slippery. Kayakers wax their boats to

Sindrei [870]

The answer is : C. reduce their input force
they put wax on their kayak to make their boat cut smoothly through the water, which make it able to obtain further distance with less input force, which will increase it's overall speed

8 0

3 years ago

Read 2 more answers

A rigid container is filled with chlorine gas. The gas has a pressure of 2.75 bar. The tank is then cooled down to -20.0oC at wh

Gnom [1K]

Answer:

Original temperature (T1) = - 37.16°C

Explanation:

Given:

Gas pressure (P1) = 2.75 bar

Temperature (T2) = - 20°C

Gas pressure (P2) = 1.48 bar

Find:

Original temperature (T1)

Computation:

Using Gay-Lussac's Law

⇒ P1 / T1 = P2 / T2

⇒ 2.75 / T1 = 1.48 / (-20)

⇒ T1 = (2.75)(-20) / 1.48

⇒ T1 = -55 / 1.48

⇒ T1 = - 37.16°C

Original temperature (T1) = - 37.16°C

3 0

3 years ago

4) What volume will the gas in the balloon at right occupy at 250k? balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

3 years ago

Write the products of these double-replacement reaction. Then balance each equation. a) NaOH(aq) + Fe(NO3)3 (aq)---> Iron (II

pashok25 [27]

Answer:

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

Explanation:

Step 1: RxN

NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)

Step 2: Balance RxN

We need 3 OH's on both sides.

We also need 3 NO₃'s on both side.

This will make it so we also need 3 Na's on both side

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

6 0

3 years ago

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

RSB [31]

Answer:

0.036 g

Explanation:

0.036 g of water should be produced.

From the equation of reaction, 1 mole of HCl requires 1 mole of NaOH in order to produce 1 mole of H2O.

20 mL of 0.10 M HCl contains 20/1000 x 0.10 = 0.002 moles of HCl

46 grams of NaOH contains 46/40 = 1.15 moles of NaOH

It thus means that the HCl is a limiting reagent in the reaction.

From the equation:

1 mole HCl will produce 1 mole of H2O.

0.002 HCl with therefore produce 0.002 x 1/1 = 0.002 mole of H2O

Mass of water produced = mole x molar mass

0.002 x 18 = 0.036 g.

Hence, 0.036 g of water would be produced.

8 0

3 years ago