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Radda [10]
3 years ago
9

From the picture above, please list 3 long-term and 3 short-term impacts this natural disaster

Physics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

Long terms:

-earth its self

-economy (money)

-death

Short term:

- dirty

-damage houses

- roofing

-electricity

Explanation:

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A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to fricti
Papessa [141]

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 -  \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J

Therefore, the kinetic energy lost due to friction is 22.5 J

7 0
2 years ago
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Which magnet will produce the strongest force of attraction when placed beneath this magnet?
Kruka [31]

Answer:

B

Explanation:

3 0
3 years ago
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Pls help will give brainlist
ale4655 [162]
Potential energy

potential energy is the stored energy an object has, the bike is not moving and it just sitting on the hill, with the stored energy
3 0
2 years ago
At what common temperature will a block of wood and a block of metal both feel neither hot nor cold to the touch ?
Anastaziya [24]

When you touch an object and heat flows OUT of it, INTO your finger, you say the object feels hot.

When you touch an object and heat flows INTO it, OUT of your finger, you say the object feels cold.

If the object has the same temperature as your finger ... <em>around the mid-90s</em> ... then no heat flows in or out of your finger when you touch the object, and the object doesn't feel hot or cold.

6 0
3 years ago
In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s
DaniilM [7]

Answer:

a. i=4760 kg*m/s

b. D_U= 1.11 m

Explanation:

a)

F= 120,000N

Kinetic energy @ impact = 120,000*depth

K_E= (1/2)*85kg*(56m/s)^2

K_E=133280 J

D_U= \frac{133280J}{120000N} = 1.11 m

b)

The momentum is equal to the impulse on him from the snow so:

p=m*v

p=85kg*56m/s

i=4760 kg*m/s

7 0
3 years ago
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