From the picture above, please list 3 long-term and 3 short-term impacts this natural disaster
1 answer:
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It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
Take the square root of both side
Therefore, it will take 6.42 s for the ball to get to the ground.
Learn more: brainly.com/question/24903556
Answer:
The distance between them, x = 5809.47 m
Explanation:
Given,
The average weight of a human, w = 600 N
The charge carried by the humans, q = 1.5 C
If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,
<em></em>
Where,
= 9 x 10⁹ N m² C⁻²
Therefore
x² = 9 x 10⁹ X 1.5² / 600
= 33750000
x = 5809.46 m
Hence, the distance between the humans should be, x = 5809.47 m
Answer:
a)W=8.333lbf.ft
b)W=0.0107 Btu.
Explanation:
<u>Complete question</u>
The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.
Solution
Preload = F₀=0 lbf
Spring constant k= 200 lbf/in
Initial length of spring x₁=0
Final length of spring x₂= 1 in
At any point, the force during deflection of a spring is given by;
F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.
Change to lbf.ft by dividing the value by 12 because 1ft=12 in
100/12 = 8.333 lbf.ft
work required to compress the spring, W=8.333lbf.ft
The work required to compress the spring in Btu will be;
1 Btu= 778 lbf.ft
?= 8.333 lbf.ft----------------cross multiply
(8.333*1)/ 778 =0.0107 Btu.