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Radda [10]
3 years ago
9

From the picture above, please list 3 long-term and 3 short-term impacts this natural disaster

Physics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

Long terms:

-earth its self

-economy (money)

-death

Short term:

- dirty

-damage houses

- roofing

-electricity

Explanation:

You might be interested in
How much heat is required to convert 12.0 g of ice at -10.0°C to steam at 100.0°C. Express your answer in joules, calories, and
Kruka [31]
You can’t solve it because you don’t have c in the question
3 0
2 years ago
Chromatic aberration comes from the fact that different wavelengths of light travel at different speeds through the material of
gtnhenbr [62]

Answer:

 y_red / y_blue = 1.11

Explanation:

Let's use the constructor equation to find the image for each wavelength

         1 /f = 1 /o + 1 /i

Where f is the focal length, or the distance to the object and i the distance to the image

Red light

           1 / i = 1 / f - 1 / o

           1 / i_red = 1 / f_red - 1 / o

           1 / i_red = 1 / 19.57 - 1/30

           1 / i_red = 1,776 10-2

           i_red = 56.29 cm

Blue light

            1 / i_blue = 1 / f_blue - 1 / o

            1 / i_blue = 1 / 18.87 - 1/30

            1 / i_blue = 1,966 10-2

            i_blue = 50.863 cm

Now let's use the magnification ratio

             m = y ’/ h = - i / o

             y ’= - h i / o

Red Light

            y_red ’= - 5 56.29 / 30

            y_red ’= - 9.3816 cm

Light blue

            y_blue ’= 5 50,863 / 30

            y_blue ’= - 8.47716 cm

The ratio of the height of the two images is

            y_red ’/ y_blue’ = 9.3816 / 8.47716

            y_red / y_blue = 1,107

            y_red / y_blue = 1.11

5 0
3 years ago
A teacher points to a microscope sitting on the desk. Which conclusion best explains
Blababa [14]

Answer:

The object is sitting

Explanation:

Therefore the object cannot be in current motion as no force has been acted upon it (exept gravitational force)

8 0
3 years ago
Each proton-proton cycle generates 26.7 MeV of energy. If 9.9 Watts are generated via by the proton-proton cycle, how many billi
lina2011 [118]

Answer:

4.635 *10^12 Neutrinos

Explanation:

Here in this question, we are to determine the number of neutrinos in billions produced, given the power generated by the proton-proton cycle.

We proceed as follows;

In proton-proton cycle generates 26.7 MeV of energy and in this cycle two neutrinos are produced.

From the question, we are given that

Power P = 9.9 watts = 9.9 J/s

Watts is same as J/s

The number of proton-proton cycles required to generate E energy is N = E / E '

Where E ' = Energy generated in proton-proton cycle which is given as 26.7 Mev in the question

Converting Mev to J, we have

= 26.7 x1.6 x10 -13 J

To get the number N which is the number of proton-proton cycle required, we have;

N = 9.9 /(26.7 x1.6 x10^-13) = 2.32 * 10^12

Since we have two proton cycles( proton-proton), it automatically means 2 neutrinos will be produced.

Therefore number of neutrions produced = 2 x Number of proton-proton cycles = 2 * 2.32 * 10^12 = 4.635 * 10^12 neutrinos

8 0
3 years ago
Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of
Oliga [24]

Answer:

8.4168\times 10^{-21}\ kgm/s upward

4.725 kgm/s to the right

468.6 kgm/s southwest

1.782\times 10^{49}\ kgm/s forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s

The momentum of the proton is 8.4168\times 10^{-21}\ kgm/s upward

Bullet

p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s

The momentum of the sprinter is 1.782\times 10^{29}\ kgm/s forward

4 0
3 years ago
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