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devlian [24]
3 years ago
15

Which type of rock is made of tiny bits of animal shells? A. gabbro B. coquina C. clastic sandstone D. limestone

Physics
2 answers:
marysya [2.9K]3 years ago
8 0
Hello,



The answer is <span>C. clastic sandstone


Hope this helps
</span>
Westkost [7]3 years ago
4 0

Answer: the answer is limestone can i have brainest?

Explanation:

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a stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes th
Ksju [112]

Answer:

v=\sqrt{2gh}

Explanation:

We could use conversation of energy. Total distance the stone will cover will be

h=\frac{1}{2} g t^{2}

the Final velocity will be

v=gt\\v=g\sqrt{\frac{2h}{g} }\\ v=\sqrt{2gh}

5 0
3 years ago
La luz roja visible tiene una longitud de onda de 680 nanómetros (6,8 x 10-7 m). La velocidad de la luz es de 3.0 x108 m / s. ¿C
Lina20 [59]

Answer:

Frequency, f=4.41\times 10^{14}\ Hz

Explanation:

Visible red light has a wavelength of 680 nanometers (6.8 x 10⁻⁷ m). The speed of light is 3.0 x 10 ⁸ m / s. What is the frequency of visible red light?

It is given that,

Wavelength of a visible red light is, \lambda=6.8\times 10^{-7}\ m

Speed of light is, c=3\times 10^8\ m/s

We need to find the frequency of visible red light. It can be calculated using below relation.

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.8\times 10^{-7}}\\\\f=4.41\times 10^{14}\ Hz

So, the frequency of visible red light is 4.41\times 10^{14}\ Hz.

3 0
3 years ago
A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60
mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

Also, the east bound travels as a function of time and can be given as:

y(t) = 60t

Now,

To calculate the speed, z(t) of the train as it passes through the intersection:

Since, the road cross at right angles, thus by Pythagoras theorem:

z(t) = \sqrt{x^{2} + y(t)^{2}}

z(t) = \sqrt{70^{2} + 60t^{2}}

Now, differentiate the above eqn w.r.t 't':

\frac{dz(t)}{dt} = \frac{1}{2}.\frac{1}{sqrt{3600t^{2} + 4900}}\times 2t\times 3600

\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t

For t = 4 s:

\frac{dz(4)}{dt} = \frac{1}{sqrt{3600\times 4^{2} + 4900}}\times 3600\times 4 = 57.6\ m/s

4 0
3 years ago
Throw a paper ball towards a hard wall.
Len [333]
The answer is d hope this helps
7 0
3 years ago
How should the distance, D, between two point charges, q1 and q2, be changed to double their electric potential energy
Licemer1 [7]

The electrostatic potential energy, U, of one point charge q at position d in the presence of an electric field E is defined as the negative of the work W done by the electrostatic force to bring it from the reference position d to that position

u \:  =  \:  \frac{kq1q2}{d}

Thus, to double the electric potential energy U we need to reduce the distance of separation by half (1/2) because they are inversely proportion

6 0
3 years ago
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