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Sidana [21]
3 years ago
10

How many of the following statements about silver acetate, AgCH3COO, are true? i) More AgCH3CoO(S) will dissolve if the pH of th

e solution is reduced to 2.5 i) Less AgCH3CO0(s) will dissolve if AgNO; (s) is added to the aqueous solution iii) More AgCH3CoO(s) will dissolve if NaOH (aq) is added to the aqueous solution a) 0 b) c) 2 d) 3
Chemistry
1 answer:
shutvik [7]3 years ago
8 0

Answer:

All three statements are true

Explanation:

Solubility equilibrium of silver acetate:

AgCH_{3}COO\rightleftharpoons Ag^{+}+CH_{3}COO^{-}

  • If pH is increased then concentration of H^{+} increases in solution resulting removal of CH_{3}COO^{-} by forming CH_{3}COOH. Hence, according to Le-chatelier principle, equilibrium will shift towards right. So more AgCH_{3}COO will dissolve
  • If AgNO_{3} is added then concentration of Ag^{+} increases in solution resulting shifting of equilibrium towards left in accordance with Le-chatelier principle. So less AgCH_{3}COO will dissolve
  • Insoluble precipitate of AgOH is formed by adding NaOH in solution resulting removal of Ag^{+}. So, more AgCH_{3}COO will dissolve

Hence all three statements are true

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When the equation below is correctly balanced, the coefficient for CO2 is
vaieri [72.5K]

Answer:

The answer to your question is 4

Explanation:

Chemical reaction

                C₂H₆  +  O₂  ⇒  CO₂  +  H₂O

           Reactants    Elements    Products

                  2            Carbon              1

                  6            Hydrogen         2

                  2            Oxygen             3

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒  4CO₂  +  6H₂O

           Reactants    Elements    Products

                  4            Carbon             4

                 12            Hydrogen       12

                 14            Oxygen           14

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5 0
3 years ago
What is the pH of a 0.28 M solution of ascorbic acid
Nady [450]

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² /  [0.28 -x ]

x² + 8.0*10⁻⁵x  - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

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Answer:

c MgO

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8 0
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Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

Ionization energy, also known as ionization energy, would be the minimal amount of energy needed to free an isolated gaseous atom's or molecule's least loosely bonded electron.

First ionization energy often drops as you advance down a group on the periodic table. This occurs even though the outermost electron would be typically held less securely and can be removed with less energy since it travels farther away from the nucleus.

Therefore, Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

To know more about Ionization energy

brainly.com/question/16243729

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