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3 years ago

I’m confused how to do this

Chemistry

1 answer:

Stels [109]3 years ago

7 0

Answer:

B. P (Phosphorus)

Explanation:

The element is be phosphorus.

This is true because phosphorus has a larger atomic radius than carbon. If you move than the group, elements gain additional electron shell. That additional electron shell keeps electrons far from the nucleus of the atom. This actually increases the atomic radius. Also, phosphorus is more electronegative than aluminum because phosphorus itself is a non-metal and non-metals are generally electronegative while aluminum is a metal and electropositive.

Phosphorus has a lower ionization energy than argon because the ionization energy across the period (i.e from left to right) increases and across period 3, you will find phosphorus first before argon in the periodic table.

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A redox reaction can also be a?

AveGali [126]

Losing eltron is the answer

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3 years ago

When weak acids react with strong bases, the H+ from the weak acid is transferred to the:

frosja888 [35]

It teacts with OH and makes water and salt

5 0

3 years ago

Give regents and mechanism

Kryger [21]

Answer:

Reagents: 1) $BH_3$ 2) $H_2_O2$ , $OH^-$

Mechanism: Hydroboration

Explanation:

In this case, we have a hydration of alkenes reaction. But, in this example, we have an anti-Markovnikov reaction. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: "hydroboration".

The first step of this reaction is the addition of borane ( $BH_3$ ) to the double bond. Then in the second step, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the third step, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond " $BH_2-O-OH$ ". In step number 4 we have the migration of the C-B bond to oxygen. Then in step number 5, we have the attack of $OH^-$ on the $O-BH_2$ to produce an alkoxide. Finally, the water molecule produce in step 2 will protonate the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0

3 years ago

HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED

kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0

3 years ago

QUESTION 3 A series of electrolytic deposition experiments is conducted. In each case, 10.0 Faradays is passed through the indiv

Neporo4naja [7]

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

Learn more: brainly.com/question/967776

6 0

2 years ago