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Likurg_2 [28]
3 years ago
5

I’m confused how to do this

Chemistry
1 answer:
Stels [109]3 years ago
7 0

Answer:

B. P (Phosphorus)

Explanation:

The element is be phosphorus.

This is true because phosphorus has a larger atomic radius than carbon. If you move than the group, elements gain additional electron shell. That additional electron shell keeps electrons far from the nucleus of the atom. This actually increases the atomic radius. Also, phosphorus is more electronegative than aluminum because phosphorus itself is a non-metal and non-metals are generally electronegative while aluminum is a metal and electropositive.  

Phosphorus has a lower ionization energy than argon because the ionization energy across the period (i.e from left to right) increases and across period 3, you will find phosphorus first before argon in the periodic table.

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<u>Answer:</u> The given solution is unsaturated solution

<u>Explanation:</u>

We are given:

Solubility of NaBr = 9.19 m

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

A precipitate is defined as the insoluble salt which is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

There are three conditions:

  • When m_{\text{(calculated)}}; the solution is unsaturated
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To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}  

Where,

m_{solute} = Given mass of solute (sodium bromide) = 91.3 g

M_{solute} = Molar mass of solute (sodium bromide) = 103 g/mol

W_{solvent} = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

\text{Calculated molality of NaBr}=\frac{91.3\times 1000}{103\times 115}\\\\\text{Calculated molality of NaBr}=7.71m

As, the calculated solubility is less than the given solubility. So, the solution will be unsaturated.

Hence, the given solution is unsaturated solution

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