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Zielflug [23.3K]
3 years ago
15

Which of the following personal items are permitted to be at your workstation in the organic laboratory? Select all that apply.

a. Pen or pencil b. Drinking water bottle c. I-Pad d. Lab manual e. Cell phone
Chemistry
1 answer:
lapo4ka [179]3 years ago
6 0

Explanation:

While working in a laboratory it is necessary to be free from any kind of distraction. This is because a distraction while working in a laboratory can lead to serious consequences.

For this it is important to put all your electronic devices like mobile phones, tablets etc in your backpack. Also, you should not carry any kind of eatable, water bottle or anything into the lab.

This is because chemicals do react with food items. Hence, then food does not remain fit for consumption.

Thus, we can conclude that pen or pencil and lab manual personal items are permitted to be at your workstation in the organic laboratory.

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g The boiling of water is a Question 4 options: chemical and physical damage chemical change because a gas (steam) is given off
Strike441 [17]

Answer:

physical change because the gaseous water is chemically the same as the liquid

Explanation:

Matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are; solid, liquid and gas.

A physical change can be defined as a type of change that only affects the physical form of a chemical substance (matter) without having any effect on its chemical properties. Thus, a physical change would only affect the physical appearance and properties of a chemical substance (matter) but not its chemical properties.

This ultimately implies that, a physical change result in a change of matter from one form or phase (liquid, solid or gas) to another without a corresponding change in chemical composition.

Hence, the boiling of water is considered to be a physical change because the gaseous water is chemically the same as the liquid i.e there isn't any changes in chemical composition of water when boiling.

8 0
2 years ago
Write the quantities 3 x 10^-4 cm and 3 x 10^4 km in ordinary notation
Goshia [24]
To write quantities in ordinary notation, you need to notice the power of the exponent.
If the power is positive, then you move the decimal point to the right by the number the power in exponent tells you.
If the power is negative, then you move the decimal point to the left by the number the power in exponent tells you.

We have:
3 x 10^-4 : the power of exponent is negative, therefore, we will move the decimal point 4 places to the left.
3 x 10^-4 = 0.0003 km

3 x 10^4 : he power of exponent is positive, therefore, we will move the decimal point 4 places to the right.
3 x 10^4 = 30000 km
6 0
3 years ago
Which of the following is not an example of a polymer?
drek231 [11]
Sucrose <span>is not an example of a polymer. The answer is letter C. Polystyrene, Nylon and PVC or poly vinyl chloride are examples of polymer</span>
7 0
3 years ago
Read 2 more answers
Describe the organism that scientists believe was responsible for changing the composition of the early atmosphere. What is it c
lara31 [8.8K]
The early atmosphere was probably mostly carbon dioxide, with little or no oxygen. <span>The proportion of oxygen went up because of </span>photosynthesis. The photosynthesis was conducted from <span>tiny organisms.
</span><span>cyanobacteria, or blue-green algae. </span><span>
They </span>used sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen. This change to the atmosphere was very important because the <span>breathable air we enjoy today was created.</span>
4 0
3 years ago
Read 2 more answers
A sample of diborane gas (B2H6), a substance that bursts into flame when exposed to air, has a pressure of 345 torr at a tempera
Hitman42 [59]

Answer:

The final volume is 3.07L

Explanation:

The general gas law will be used:

P1V1 /T1 = P2V2 /T2

V2 =P1 V1 T2 / P2 T1

Give the variables to the standard unit:

P1 = 345 torr = 345 /760 atm = 0.4539atm

T1 = -15°C = -15 + 273 = 258K

V1 = 3.48L

T2 = 36°C = 36+ 273 = 309K

P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm

V2 = ?

Equate the values into the gas equation, you have:

V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258

V2 = 488.0877 /158.8764

V2 = 3.07

The final volume is 3.07L

8 0
3 years ago
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