Question

A cell membrane is 0,0000005 m thick and has an electric potential difference between its surfaces of 0,10 V. What is the electric field within the membrane?

Answer 1

Answer:

Electric field in the membrane is given as

$E = 2 \times 10^5 V/m$

Explanation:

As we know that electric field in a region is related to its potential difference given by the formula

$E = \frac{\Delta V}{\Delta x}$

here we know that

$\Delta V = 0.10 V$

$\Delta x = 0.0000005 m$

so we have

$E = \frac{0.10}{0.0000005}$

$E = 2 \times 10^5 V/m$