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3 years ago

Calculate the volume of a balloon filled with 0.0940 grams of helium, given the fact that the density of helium is 0.179 g/L

Chemistry

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

Answer: 1.027 x 10^6 g= 1027kg

In this question, you are given the volume of the blimp (2.027×10^5 ft^3) and the density of the gas(0.179g/L). To answer this question, you need to convert the volume unit into liter. The calculation would be: 2.027×10^5 ft^3 x 28.3168L/ft3= 57.398 x 10^5L= 5.74x10^6L

Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg

Explanation:

i hope it helps

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Answer:

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Explanation:

Step 1:

Determination of the Neutron of both isotopes. This is illustrated below.

For isotope y xA:

Mass number = y

Atomic number = x

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Atomic number = proton number = x

Mass number = Proton + Neutron

y = x + Neutron

Rearrange

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For isotope (y + 1) xA:

Mass number = y + 1

Atomic number = x

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Atomic number = proton number = x

Mass number = Proton + Neutron

y + 1 = x + Neutron

Rearrange

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Step 2:

Determination of the difference between the neutron number of both isotopes. This is illustrated below:

For isotope y xA:

Neutron number = y – x

For isotope (y + 1) xA:

Neutron number = y + 1 – x

Difference in neutron number

=> (y + 1 – x) – (y – x)

=> y + 1 – x – y + x

Rearrange

=> y – y + 1 – x + x

=> 1

Therefore, the difference in the neutron number of both isotopes is 1

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