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3 years ago

Calculate the volume of a balloon filled with 0.0940 grams of helium, given the fact that the density of helium is 0.179 g/L

Chemistry

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

Answer: 1.027 x 10^6 g= 1027kg

In this question, you are given the volume of the blimp (2.027×10^5 ft^3) and the density of the gas(0.179g/L). To answer this question, you need to convert the volume unit into liter. The calculation would be: 2.027×10^5 ft^3 x 28.3168L/ft3= 57.398 x 10^5L= 5.74x10^6L

Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg

Explanation:

i hope it helps

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What is the ratio of lactic acid (Ka = 1.37x^10-4) to lactate in a solution with pH =4.29

hram777 [196]

Henderson–Hasselbalch equation is given as,

pH = pKa + log [A⁻] / [HA] -------- (1)

Solution:

Convert Ka into pKa,

pKa = -log Ka

pKa = -log 1.37 × 10⁻⁴

pKa = 3.863

Putting value of pKa and pH in eq.1,

4.29 = 3.863 + log [lactate] / [lactic acid]

Or,

log [lactate] / [lactic acid] = 4.29 - 3.863

log [lactate] / [lactic acid] = 0.427

Taking Anti log,

[lactate] / [lactic acid] = 2.673

Result:

2.673 M lactate salt when mixed with 1 M Lactic acid produces a buffer of pH = 4.29.

6 0

4 years ago

An irregularly-shaped piece of copper (Cu) has a mass of 55.0 grams. What is the volume in cm³ of this piece of copper if its de

vredina [299]

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question we have

$volume = \frac{55}{8.96} \\ = 6.138392...$

We have the final answer as

Hope this helps you

8 0

3 years ago

Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at

kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

$r = \frac{1 }{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

Squaring both sides, we get

$(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}$

Solve for <em>M</em>₂:

$M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}$

$M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}$

$= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}$

7 0

3 years ago

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

concentration 2 = (287 x 1.6) / 412

Simplification

concentration 2 = 459.2 / 412

Result

concentration 2 = 1.11 M

5 0

4 years ago

If acid precipitation rain changes the ph of a pond from 7.0 to 5.0, the level of hydrogen ion has changed by a factor of ______

Karolina [17]

When pH=7, [H⁺] =10⁻⁷.
When pH=5, [H⁺]=10⁻⁵.

10⁻⁵/10⁻⁷ =10²=100
The level of hydrogen ions increased by factor 100.

5 0

4 years ago