Answer:
282 m
Explanation:
Given:
v₀ = 20.1 m/s
v = 33.2 m/s
t = 10.6 s
Find: Δx
Δx = ½ (v + v₀) t
Δx = ½ (33.2 m/s + 20.1 m/s) (10.6 s)
Δx ≈ 282 m
Answer:
the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person in cart, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
acceleration due to gravity, g = 9.8 m/s²
final speed of the cart before it goes up the hill, v = 19 m/s
Apply the principle of conservation of energy;
![mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m](https://tex.z-dn.net/?f=mgh_%7Bmax%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2_%7Bmax%7D%5C%5C%5C%5C%20gh_%7Bmax%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7Dv%5E2_%7Bmax%7D%5C%5C%5C%5Ch_%7Bmax%7D%20%3D%20%5Cfrac%7Bv%5E2_%7Bmax%7D%7D%7B2g%7D%20%5C%5C%5C%5Ch_%7Bmax%7D%20%3D%5Cfrac%7B%2819%29%5E2%7D%7B2%5Ctimes%209.8%7D%20%5C%5C%5C%5Ch_%7Bmax%7D%20%3D%2018.42%20%5C%20m)
Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
Answer:
Decreases by
times
Explanation:
The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.
The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.
In other words, the sound intensity decreases as inversely proportional to the squared of the distance. i.e. ![$\frac{1}{r^2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7Br%5E2%7D%24)
In the context when the distance was 3 m, the intensity of the sound was = ![$\frac{1}{9}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B9%7D%24)
But when the distance became 6 cm or 0.06 m, the sound intensity decreases by = ![$\frac{1}{0.06^2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B0.06%5E2%7D%24)
=
times
The greater the cross-sectional area of an object, the greater the amount of air resistance it encounters since it collides with more air molecules. ... It will have to accelerate for a longer period of time before there is enough upward air resistance to balance the downward force of gravity.