Speed =dist./time
=73.4/5
=14.68 km/hr
        
                    
             
        
        
        
Answer:
when completing a science experiment it is important to run multiple tests do as to reduce the risk of any outliers of false results
 
        
             
        
        
        
Explanation:
Distance covered by the particle is given by:
Distance (d) = rate (v) × time (t)                
Speed of Mary, v₁ = 50 mph
Speed of Jim, v₂ = 60 mph
It is assumed that, Mary and Jim leave at the same time. After one hour, Jim is 10 miles ahead.
Distance travelled by Jim, d₁ = (60t + 10)
Distance travelled by Mary, d₂ = 50t
The distance between Mary and Jim is greater than or equal to 100 miles.



So, Jim takes is 9 hours more than Mary to cover same distance. Hence, this is the required solution.
 
        
             
        
        
        
Answer:
a. I = 0.76 A
b. Z = 150.74 
c. RL₁ = 34.41  ,  RL₂ = 602.58 
d. RL₂ = 602.58 
Explanation:
V₁ = 116 V , R₁ = 77.0 Ω , Vc = 364 V ,  Rc = 473 Ω 
a. 
Using law of Ohm 
V = I * R
I = Vc / Rc =  364 V / 473 Ω 
I = 0.76 A 
b. 
The impedance of the circuit in this case the resistance, capacitance and inductor 
V = I * Z 
Z = V / I 
Z = 116 v / 0.76 A 
Z = 150.74 
c. 
The reactance of the inductor can be find using 
Z² = R² + (RL² - Rc²)
Solve to RL'
RL = Rc (+ / -) √ ( Z² - R²) 
RL = 473 (+ / -)  √ 150.74² 77.0²
RL = 473 (+ / -)  (129.58)
RL₁ = 34.41  ,  RL₂ = 602.58 
d.
The higher value have the less angular frequency   
RL₂ = 602.58 
ω = 1 / √L*C 
ω = 1 / √ 602.58 * 473 
f = 285.02 Hz
 
        
             
        
        
        
Answer:
Explanation:
The sandpaper block did not move because the forces of friction and gravity were balanced.