a population of size 2000 at time t equals0, where t is measured in years. 1. Suppose Jonesville's population grows by 170 peo ple per year. 2. Suppose the population of Smithville grows by 7% per year.
1 answer:
Answer:
1.
2.
Step-by-step explanation:
For case 2 the population grows by 170 per year. Therefore for year t=0 its 2000 and t=1 then the population is 2170 and t=2 population is 2340. We can express the sequence as:
We know the difference is d=170 and n=1,2,3....:
Case two can be define by:
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Answer:
12
Step-by-step explanation:
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25 = 2p + 1
24 = 2p
12 = p
f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33
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Our function is:
Now, if is a factor of then must satisfy the equation:
So,
Putting
We get,
So, the value of 'a' for the given expression is 1281.
1.403 > 1.1 1.1 = 1.100 1.403>1.100
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