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Firdavs [7]
3 years ago
12

Select the correct value for the indicated bond angle in each of the following compounds: O-S-O angle of SO2 F-B-F angle of BF3

Cl-S-Cl angle of SCI2 O-C-O angle of CO2 F-P-F angle of PF3 H-C-H angle of CH4
Chemistry
1 answer:
Stels [109]3 years ago
7 0

Answer:

(A) O-S-O bond angle of SO₂ molecule = 119°

(B) F-B-F bond angle of BF₃ molecule = 120°

(C) Cl-S-Cl bond angle of SCl₂ molecule = 103°

(D) O-C-O bond angle of CO₂ molecule = 180°

(E) F-P-F bond angle of PF₃ molecule = 96.3°

(F) H-C-H bond angle of CH₄ molecule = 109.5°

Explanation:

Bond angle refers to the angle between two adjacent chemical bonds in a molecule. The bond angle is different for different molecular geometry.

The Valence shell electron pair repulsion theory predicts the molecular geometry and shape of the given molecule by the number of lone pairs on central atom and number of atoms bonded to central atom.

(A) SO₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 1

<u>Therefore, the shape of SO₂ molecule is bent and the O-S-O bond angle is 119°.</u>

(B) BF₃ molecule

The number of atoms bonded to B = 3

Number of lone pairs on B = 0

<u>Therefore, the shape of BF₃ molecule is trigonal planar and the F-B-F bond angle is 120°.</u>

(C) SCl₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 2

<u>Therefore, the shape of SCl₂ molecule is bent and the Cl-S-Cl bond angle is 103°.</u>

(D) CO₂ molecule

The number of atoms bonded to C = 2

Number of lone pairs on C = 0

<u>Therefore, the shape of CO₂ molecule is linear and the O-C-O bond angle is 180°.</u>

(E) PF₃ molecule

The number of atoms bonded to P = 3

Number of lone pairs on P = 1

<u>Therefore, the shape of PF₃ molecule is trigonal pyramidal and the F-P-F bond angle is 96.3°.</u>

(F) CH₄ molecule

The number of atoms bonded to C = 4

Number of lone pairs on C = 0

<u>Therefore, the shape of CH₄ molecule is tetrahedral and the H-C-H bond angle is 109.5°.</u>

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6 0
3 years ago
How many grams of PH3 will be produced if 6.0 l of H2 are used?
elena-s [515]

Mass of PH3= 6.086 g

<h3>Further explanation</h3>

Given

6.0 L of H2

Required

mass of PH3

Solution

Reaction

P4 + 6H2 → 4PH3

Assumed at STP ( 1 mol gas=22.4 L)

Mol of H2 for 6 L :

= 6 : 22.4 L

= 0.268

From the equation, mol PH3 :

= 4/6 x moles H2

= 4/6 x 0.268

= 0.179

Mass PH3 :

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= 6.086 g

5 0
2 years ago
In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False
Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .          

sodium potassium move 3Na+ outside the cells          

and  moving 2k+ inside the cells                        

so that we can say that given statement is false    

Answer FALSE                                                      

6 0
3 years ago
What is the pH of pure water at 40.0°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233
Sergeeva-Olga [200]

Answer:

PH= 6.767     (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

[H_{3}O^{+}  ] [OH^{-}  ] = Kw = 2.92*10^{-14} M^{2}   \\\\

at 40ºC

[H_{3}O^{+}  ] = [OH^{-}  ]

[H_{3}O^{+}  ]^{2} = 2.92*10^{-14} M^{2}

[H_{3}O^{+}  ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M

PH= -log10[H_{3}O^{+}  ] = -log10(1.71*10^{-7} ) = 6.767

7 0
3 years ago
Percent Error Problems – Find the percent error for each problem below.
Citrus2011 [14]

% error = 3.4 %

Percent error = |accepted value - experimental value|/accepted value × 100%

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5 0
3 years ago
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