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saw5 [17]
3 years ago
15

1. Suppose the synthesis of an amino acid was accomplished by four enzymes encoded by four genes that formed an operon. Draw a m

odel of the operon showing how it could be controlled by negative regulation both at the level of transcription initiation and elongation via attenuation.

Biology
1 answer:
vivado [14]3 years ago
7 0

I have attached lac operon model having 4 genes. See attachment for better understanding.

Answer:

The Lac operon is controlled  by two signals.

Initiation

Glucose and lactose  concentrations control the initiation of  transcription of the Lac operon through  their effects on the Lac repressor protein  and Cap.

Lactose absent (Repression)

When lactose is absent, the Lac  repressor binds the Lac operator and shuts  off expression of the operon.

Lactose present (Transcription)

Addition  of lactose increases the intracellular  concentration of a related compound,  allolactose. allolactose binds to the  Lac repressor, causing it to undergo a  conformational change that releases its grip  on the operator DNa.

Glucose absent (Repression)

When  glucose is absent, cyclic aMp (red triangle)  is produced by the cell and Cap binds to  DNA.

Glucose present (Transcription)

LacZ, the first gene of the operon,  encodes the enzyme b-galactosidase, which  breaks down lactose to galactose and  glucose.

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Answer:

Explanation:

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2) Then we can use certain reactants to precipitate the cations of the sample. For example, we can add first HCN 3N to our sample. If there is precipitation, it means that the cations Ag⁺ or Pb²⁺ are present. If not, there are other cations and we must use a different reactant to precipitate them.

3) We then add H₂S to the sample (not adding it per se, but generating it heating thioacetamide with water). If we see a black precipitate, it can be because of the cations Pb²⁺, Bi³⁺ or Cu²⁺. If we see a yellow precipitate, it corresponds to Cd²⁺. If we do not see a precipitate, we need to add other reactant.

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Sobre el mismo papel de filtro se añade NH3 2N. En el papel de filtro si existe Hg22+ y se forma una mancha blanca, gris o negro, que es una mezcla de HgClNH2 y Hg0. En la disolución se forman Ag(NH3)2+, que se puede identificar con KI dando un precipitado de AgI amarillo claro.

3 0
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Answer:

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Explanation:

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