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Bess [88]
3 years ago
15

At one moment during a walk around the block, there are four forces exerted upon Fido - a 10.0 kg dog. The forces are:

Physics
1 answer:
Ann [662]3 years ago
7 0

Explanation:

Given that,

Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)

Fnorm = 64.5 N, up

Ffrict = 27.6 N, left

Fgrav = 98 N, down

(a) Resolution of the applied force:

Horizontal component,

F_x=F\cos\theta\\\\=67\times \cos(30)\\\\=58.02\ N

Vertical component,

F_y=F\sin\theta\\\\=67\times \sin(30)\\\\=33.5\ N

(b) Net horizontal force :

F_x=58.02+(-27.6),\ \text{frictional force act in opposite direction of motion}\\\\F_x=30.42\ N

It is positive, it will act in right side

Net vertical force :

F_y=33.5+64.5+(-98),\ \text{gravitational force acts in downward direction}\\\\F_y=0

Hence, it is clear that the net force is in horizontal direction i.e. 30.42 N due right side.

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5.01×10⁴ J.

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q = Cm....................... Equation 1

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