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Novosadov [1.4K]

3 years ago

15

State the law of conversation of energy in your own words. Give an example of a situation that you have either encountered or kn

ow about in which the law of conversation of energy is demonstrated.

1 answer:

RSB [31]3 years ago

4 0

That Energy Cannot Be Created Nor Destroyed

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All of the fallowing are possible sources of error in a scientific investigation exept for

Whitepunk [10]

c adding research resources during an investigation

6 0

3 years ago

What’s the difference between the resistance of 1,000 feet of aluminum No. 14 wire and 1,000 feet of No. 14 copper wire? A. The

Lapatulllka [165]

the answer is A. The aluminum has 0.84 ohms more resistance.

3 0

3 years ago

Two identical resistors connected in series have an equivalent resistance of 4 ohms. The same two resistors, when connected in p

irina1246 [14]

Answer:

1 ohm

Explanation:

since there are two identical resistors, one resistor will be

R = $\frac{4}{2}$ =2ohm [ proven as in series $R_{e} = 2 + 2 = 4ohm$ ]

to calculate the equivalent resistance when in parallel:

$\frac{1}{R_{e} } = \frac{1}{R_{1} } + \frac{1}{R_{2}}$

so,

$\frac{1}{R_{e} } = \frac{1}{2} + \frac{1}{2}$

$R_{e} = 1ohm$

4 0

3 years ago

What is the resistance of a 600 W kettle that draws a current of 5.0 A? please answer with steps

lukranit [14]

P=I^2 *R

600 =5.0^2 *R

R=24

Answer: 24 ohms

I hope it’s correcttttttt...

5 1

3 years ago

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 10

Tema [17]

Answer:

Explanation:

(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.

Hence, his average velocity is 300m/150s=2ms^−1

(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.

Therefore, his average speed for this journey is 400m210s=1.9ms−1.

For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.

Hence, his average velocity for this case is 200m/210s=0.95ms^−1

7 0

3 years ago