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Novosadov [1.4K]
3 years ago
15

State the law of conversation of energy in your own words. Give an example of a situation that you have either encountered or kn

ow about in which the law of conversation of energy is demonstrated.
Physics
1 answer:
RSB [31]3 years ago
4 0
That Energy Cannot Be Created Nor Destroyed
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This expression means that the negative terminal (-) is connected to the metal chassis or engine, which means that all voltages used for the electrical devices in the car are measured with respect to the car's chassis or engine. 
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How many electrons does eaach shell hold?
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Each electron holds 2(n2)
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3 years ago
ASAP answer right and I will do a giveaway
Olenka [21]

Explanation:

Ans 1 ) As the gravity of a planet increases, there will be increase in thickness of atmosphere around that planet. The gravitational force of the planets holds the bulks of molecules of atmosphere (as gas will need higher escape velocity).

Ans 2) Mars is the easier planets among all other planets in our solar system as it lies in habitable zone and it as a moderate gravity (where live can survive). Well, there's lot of resources too.

Thanks for asking

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3 years ago
(10 points) A spring with a 7-kg mass and a damping constant 12 can be held stretched 1 meters beyond its natural length by a fo
Ierofanga [76]

Answer:

......................

8 0
3 years ago
A planet of mass m 6.75 x 1024 kg is orbiting in a circular path a star of mass M 2.75 x 1029 kg. The radius of the orbit is R 8
Umnica [9.8K]

Answer:

The orbital period of the planet is 387.62 days.

Explanation:

Given that,

Mass of planetm =6.75\times10^{24}\ kg

Mass of star m'=2.75\times10^{29}\ kg

Radius of the orbitr =8.05\times10^{7}\ km

Using centripetal and gravitational force

The centripetal force is given by

F = \dfrac{mv^2}{r}

F=m\omega^2r

We know that,

\omega=\dfrac{2\pi}{T}

F=m(\dfrac{2\pi}{T})^2r....(I)

The gravitational force is given by

F = \dfrac{mm'G}{r^2}....(II)

From equation (I) and (II)

m(\dfrac{2\pi}{T})^2r=\dfrac{mm'G}{r^2}

Where, m = mass of planet

m' = mass of star

G = gravitational constant

r = radius of the orbit

T = time period

Put the value into the formula

T^2=\dfrac{4\pi^2R^3}{m'G}

T^2=\dfrac{4\times(3.14)^2\times(8.05\times10^{7})^3}{2.75\times10^{29}\times6.67\times10^{-11}}

T=2\times3.14\times\sqrt{\dfrac{(8.05\times10^{10})^3}{2.75\times10^{29}\times6.67\times10^{-11}}}

T =3.34\times10^{7}\ s

T= 387.62\days

Hence, The orbital period of the planet is 387.62 days.

4 0
3 years ago
Read 2 more answers
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