Answer:
the moment of inertia of the wheel is is 6.245 kg.m²
Explanation:
Given;
applied force, f = 22.04 N
radius of the wheel, r = 0.34 m
angular acceleration, a = 1.2 rad/s²
The moment of inertia of the wheel is calculated as;
![I = \frac{\tau}{\alpha } \\\\I = \frac{Fr}{\alpha } \\\\I = \frac{22.04 \ \times \ 0.34 }{1.2} \\\\I = 6.245 \ kg.m^2](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B%5Ctau%7D%7B%5Calpha%20%7D%20%5C%5C%5C%5CI%20%3D%20%5Cfrac%7BFr%7D%7B%5Calpha%20%7D%20%5C%5C%5C%5CI%20%3D%20%5Cfrac%7B22.04%20%5C%20%5Ctimes%20%5C%200.34%20%7D%7B1.2%7D%20%5C%5C%5C%5CI%20%3D%206.245%20%5C%20kg.m%5E2)
Therefore, the moment of inertia of the wheel is is 6.245 kg.m²
Atmosphere is one but that’s all I know
The direction of the fourth displacement is θ = 12.775 ( south of west)
Explanation:
write down the values in the question,
The passage is 180m west, 290m in the direction 45° east of south, 280m at 30° east of north.
x = 290 × cos 45° + 280 × sin 30° -180
x=165.06 m
y= 280 cos ( 30° - 290 × sin (45°)
y= 37.426°
θ = tan ^-1 (y/x) = tan^-1 (37.426 / 165.06)
θ= 12.775° ( south of west)
<span>One function of the skeletal system is to protect the internal organs.
true/false
The answer to your question is: True.
</span>