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3 years ago

Life cycle of a medium mass star

1 answer:

8 0

Our sun is a medium mass star, so it wouldn't be too different from the sun's life cycle. It is born, lives for about 10 billion years and then dies. ... As a medium mass star nears the end of its life, it runs out of hydrogen which it has been fusing onto helium in its core for its whole life.

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Suppose you are standing on a scale in an elevator that is accelerating upward. Will the scale read your weight as larger for sm

Marta_Voda [28]

Answer:

following are the solution to this question:

Explanation:

When I stand at such a scale in an elevated that's already rising upwards, its scale would appear to also be 0 because of free fall and would often reveal that weight whenever the lift is stable.

In this, the free fall is also known as the object, that is influenced exclusively by gravity, and an object operating only through the influence of gravity is said to be in a free-fall state.

7 0

3 years ago

How would "you" define critical thinking?

nasty-shy [4]

Answer:

Critical thinking is the analysis of facts to form a judgment. The subject is complex, and several different definitions exist, which generally include the rational, skeptical, unbiased analysis, or evaluation of factual evidence

Explanation:

8 0

3 years ago

State Pascal’s law. (2) b) The area of one end of a U-tube is 0.01 m2 and that of the other

Ray Of Light [21]

Answer:

Pascal Law's says that:

If the area of one end of a U-tube is A, and the area of the other end is A'. then if we apply a force F in the first end (the one of area A), the force experienced at the other end must be:

F' = F*(A'/A).

b) Now we can apply this to our particular case:

if the area of one end is 0.01m^2, and the area of the other end is 1m^2

Then we have:

A = 0.01m^2

A' = 1m^2

So, if now we apply a force F in the first end, the force experienced at the other end will be:

F' = F*(1m^2/0.01m^2) = F*100

This means that the force in the other end must be 100 times the force in the first end.

3 0

3 years ago

A car has a mass of 1,000 kilograms. The weight of the car is blank newtons. Use g = 9.8 N/kg for gravity.

Komok [63]

The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
So the car has a weight of 9800 N.

3 0

3 years ago

If you weigh 670 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an

LekaFEV [45]

The weight of an object at the surface of a planet is given by:
$F=mg$
where m is the mass and g is the gravitational acceleration, given by
$g= \frac{GM}{r^2}$
where G is the gravitational constant, M is the planet's mass, and r the radius of the planet.

At Earth's surface, $g=9.81 m/s^2$ . Since we know the weight of the person at Earth's surface, F=670 N, we can find his mass:
$m= \frac{F}{g}= \frac{670 N}{9.81 m/s^2}=68.3 kg$

Now we have to calculate the value of g at the surface of the neutron star. The mass of the neutron star is 25 times the Sun's mass:
$M=25 \cdot 1.99 \cdot 10^{30}kg=4.98 \cdot 10^{31} kg$

While its radius is:
$r= \frac{d}{2}= \frac{25.0 km}{2}=12.5 km = 12500 m$

Therefore, the value of g at the neutron star surface is
$g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11}Nm^2/kg^2)(4.98 \cdot 10^{31} kg)}{(12500 m)^2}=2.12 \cdot 10^{13} m/s^2$

Therefore, the weight of the person at the surface of the neutron star would be
$F' = mg = (68.3 kg)(2.12 \cdot 10^{13} m/s^2 )=1.45 \cdot 10^{15} N$

5 0

3 years ago