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iris [78.8K]
4 years ago
12

Defining Mechanical Advantage and Efficiency

Physics
2 answers:
Volgvan4 years ago
4 0

Answer:

hola como estas she cartoon Chino

qaws [65]4 years ago
3 0

Answer:

1. B

2.D

Explanation:

I took the Assignment

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Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19
aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

                                                   = 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

  F = kq₁q₂ / r²

-Solve for r²

  r² = kq₁q₂ / F

-Substitution

  r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

  r² = 2.306 x 10⁻²⁸ / 1.2

  r² = 1.922 x 10⁻²⁸

-Result

  r = 1.386 x 10⁻¹⁴ m

7 0
4 years ago
If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

the secondary load resistance, R_S = 250 Ω

Determine the turns ratio;

K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
4 years ago
The threshold of hearing is defined as the minimum discernible intensity of the sound. It is approximately 10−12w/m2. Find the
Monica [59]

Answer:

The distance d from the car at which the sound from the stereo can still be discerned = 97720.5 m

Explanation:

Sound intensity heard at distance is related to the distance with the relation = (power of sound at the source)/(surface area of the wall of an imaginary sphere at the distance in question)

I = P/4πd²

Assuming the car has 2 speakers,

P = 0.06 W × 2 = 0.12 W

d = ?

For the intensity of the least discernible sound,

I = 10⁻¹² W/m²

10⁻¹² = 0.12/4πd²

d = 97720.5 m

8 0
3 years ago
The force of the pulley is 652 newtons. It accelerates at 53 m/s. How much does the object weigh. a 1230 grams b 1.230 gram c 12
RoseWind [281]

Answer:

d. 12.30 grams

Explanation:

Given the following data;

Force = 652 N

Acceleration = 53 m/s²

To find how much the object weigh, we would need to determine its mass;

Force = mass * acceleration

652 = mass * 53

Mass = 652/53

<em>Mass = 12.30 grams.</em>

<em>Therefore, the object weighs 12.30 grams. </em>

5 0
3 years ago
La velocidad del sonido en el aire es 340 m/s. Desde que se produjo el relámpago hasta que se oyó el trueno han transcurrido 8 s
scoundrel [369]

Answer:

Distancia = 42.5 metros

Explanation:

Dados los siguientes datos;

Velocidad del sonido = 340 m/s

Tiempo = 8 segundos

Para encontrar la distancia desde la que se escuchó el sonido;

Distancia = velocidad/tiempo

Sustituyendo en la fórmula, tenemos;

Distancia = 340/8

Distancia = 42.5 metros

8 0
3 years ago
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