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Vadim26 [7]
4 years ago
5

How is precipitation related to high- and low-pressure air

Physics
1 answer:
pentagon [3]4 years ago
7 0

Answer:

The high-pressure region refers to the condition where the cold and dense air sinks and makes the atmosphere stable, forming clear sky or presence of low clouds in the sky.

On the other hand, the low-pressure region refers to the condition where the hot and less dense air rises upward, and with the presence of a sufficient amount of water content in the air, it gives rise t the formation of the clouds and eventually leads to the occurrence of rainfall.

This is how the process of precipitation is related to the high and the low-pressure air, where the low-pressure zone results in precipitation and high-pressure zone results in a clear sky.

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If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter incr
arlik [135]

<u>In modern physics</u>, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T

as:

P\alpha T^4

where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.

then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{T_{2}^4}

As

T_{2}=4T_{1}

Then

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{(4T_{1})^4}

then

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  • The factor will the total energy radiated per second per square meter increase = 256
5 0
3 years ago
How to find wavelength
Andrews [41]
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4 0
3 years ago
Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at −12 m/s when
nignag [31]
<h2>Given that,</h2>

Mass of two bumper cars, m₁ = m₂ = 125 kg

Initial speed of car X is, u₁ = 10 m/s

Initial speed of car Z is, u₂ = -12 m/s

Final speed of car Z, v₂ = 10 m/s

We need to find the final speed of car X after the collision. Let v₁ is its final speed. Using the conservation of momentum to find it as follows :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v₁ is the final speed of car X.

m_1u_1+m_2u_2-m_1v_1=m_2v_2\\\\m_2v_2=m_1u_1+m_2u_2-m_2v_2\\\\m_1v_1=125\times 10+125\times (-12)-125\times 10\\\\v_1=\dfrac{-1500}{125}\\\\v_1=-12\ m/s

So, car X will move with a velocity of -12 m/s.

3 0
3 years ago
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gavmur [86]

Answer:

Explanation:the atom consists of a tiny nucleus at its center which is surrounded by a moving electrons. The nucleus contains a positively charged proton equal in size with the negatively charged electrons . The nucleus also may contain neutrons which have the same mass with the protons but no charge is neutral.

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ahrayia [7]

Answer:

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