All categories

3 years ago

How is precipitation related to high- and low-pressure air

Physics

1 answer:

pentagon [3]3 years ago

7 0

Answer:

The high-pressure region refers to the condition where the cold and dense air sinks and makes the atmosphere stable, forming clear sky or presence of low clouds in the sky.

On the other hand, the low-pressure region refers to the condition where the hot and less dense air rises upward, and with the presence of a sufficient amount of water content in the air, it gives rise t the formation of the clouds and eventually leads to the occurrence of rainfall.

This is how the process of precipitation is related to the high and the low-pressure air, where the low-pressure zone results in precipitation and high-pressure zone results in a clear sky.

You might be interested in

PLEASE HELP

lawyer [7]

I SAID don’t copy from internet but u did

Explanation:

5 0

3 years ago

What includes a distance and a direction? A. Displacement B. Velocity C. Speed D. Acceleration

iren [92.7K]

hi <3

the correct option would be A. displacement. displacement is distance in a direction

hope this helps :)

7 0

3 years ago

Read 2 more answers

In your own words, explain Newton’s first law of motion.

Over [174]

Newton's first law of motion states that. an object on the rest or motion is stay the same unless external force applied on it.

5 0

3 years ago

Read 2 more answers

When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the

KonstantinChe [14]

Answer:

The ratio is KE : TM = 0.75

Explanation:

from the question we are told that

The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical energy of the mass is mathematically represented as

$TM = \frac{1}{2} * k * A^2$

Here k is the spring constant , A is the total displacement of the the mass from maximum compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

$TM = KE + PE$

=> $KE = TM - PE$

Here the potential energy of the mass is mathematically represented as

$PE = \frac{1}{ 2} * k * [ x ]^2$

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is

$x = \frac{A}{2}$

$PE = \frac{1}{ 2} * k * [ \frac{A}{2} ]^2$

$KE = \frac{1}{2} * k * A^2 - \frac{1}{2} * k * [\frac{A}{2} ]^2$

=> $KE = \frac{1}{2} * k * A^2 - \frac{1}{8} * k * A ^2$

=> $KE = 0.375 * k * A^2$

So the ratio of $KE : TM$ is mathematically represented as

$\frac{KE}{TM} = \frac{0.375 k A^2 }{0.5 k A^2}$

=> $\frac{KE}{TM} = 0.75$

3 0

3 years ago

A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.

AysviL [449]

Answer:

2.28

Explanation:

From mirror formula,

1/f = 1/u+1/v .......... Equation 1

Where f = focal length of the mirror, v = image distance, u = object distance.

Note: The focal length mirror is positive.

make v the subject of the equation,

v = fu/(u-f)............ Equation 2

Given: f = 2.5 cm, u = 1.4 cm

Substitute into equation 2

v = 2.5(1.4)/(1.4-2.5)

v = 3.5/-1.1

v = -3.2 cm.

Note: v is negative because it is a virtual image.

But,

Magnification = image distance/object distance

M = v/u

Where M = magnification.

Given: v = 3.2 cm, u = 1.4 cm

M = 3.2/1.4

M = 2.28.

Thus the magnification of the tooth = 2.28.

3 0

3 years ago