Answer:
To find the circumference (orbit) of an object, you use Pi x Diameter.
As you have the circumference of B, you divide it by Pi to get the Diameter.
So 120 divided by 3.141592654 = 38.2 minutes for the Diameter.
As' radius and Diameter will be 3x greater than B.
38.2 x 3 = 114.6
To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes
HOPE THIS HELPS AND PLS MARK AS BRAINLIEST
THNXX :)
Answer:
The velocity of a falling object
Explanation:
The positive X axis is towards right and positive Y axis is towards up, so North direction is positive
A vector with less than 1 magnitude is not negative, because its magnitude may be in between 0 and 1 which is positive vector.
Any vector whose magnitude is greater than 1 is never be a negative vector.
The velocity of a falling object is towards bottom, that is towards negative Y axis. So that vector is negative.
Answer:
Given values of Planck Constant are equivalent in English system and metric system.
Explanation:
Value of Planck's constant is given in English system as 4.14 x 10⁻¹⁵eV s.
Converting this in to metric system .
We have 1 eV = 1.6 x 10⁻¹⁹ J
Converting
4.14 x 10⁻¹⁵eV s = 4.14 x 10⁻¹⁵x 1.6 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ Joule s
So Given values of Planck Constant are equivalent in English system and metric system.
Answer:
23.52092 J
Explanation:
m = Mass of block = 6.79 kg
s = Sliding distance = 2.82 m
= Angle of slide = 20.7°
= Coefficient of kinetic friction = 0.425
g = Acceleration due to gravity = 9.8 m/s²
Work done by the force of gravity is given by

The work done by the force of gravity is 23.52092 J
Answer:
<em> The elastic potential energy stored in the bungee cord = 20 J</em>
Explanation:
potential energy: This is the energy possessed by a body due to its position. The S.I unit of energy is Joules. The mathematical expression for elastic potential energy is given below
E = 1/2ke²................ Equation 1
Where E = elastic potential energy of the spring, k = force constant of the spring, e = extension
<em>Given: K = 10 N/m, e = 2.00 m</em>
<em>Substituting these values into Equation 1</em>
<em>E = 1/2(10)(2)²</em>
<em>E = 5×4</em>
<em>E = 20 Joules.</em>
<em>Therefore the elastic potential energy stored in the bungee cord = 20 J</em>
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