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Vadim26 [7]
4 years ago
5

How is precipitation related to high- and low-pressure air

Physics
1 answer:
pentagon [3]4 years ago
7 0

Answer:

The high-pressure region refers to the condition where the cold and dense air sinks and makes the atmosphere stable, forming clear sky or presence of low clouds in the sky.

On the other hand, the low-pressure region refers to the condition where the hot and less dense air rises upward, and with the presence of a sufficient amount of water content in the air, it gives rise t the formation of the clouds and eventually leads to the occurrence of rainfall.

This is how the process of precipitation is related to the high and the low-pressure air, where the low-pressure zone results in precipitation and high-pressure zone results in a clear sky.

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A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.
Likurg_2 [28]

Answer:

Part a)

\phi = -4.76 \times 10^{-3} Nm^2/C

Part b)

\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C

Explanation:

Part a)

Electric flux entering into the base

so it is given as

\phi = E.A

\phi = - EA

\phi = -(1.64)(\pi r^2)

\phi = -(1.64)(\pi\times 0.0304^2)

\phi = -4.76 \times 10^{-3} Nm^2/C

Part b)

Now since we know that there is no enclosed charge in the hemisphere

so net flux must be zero

\phi_{curved} + \phi_{flat} = 0

\phi_{curved} - 4.76 \times 10^{-3} = 0

\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C

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2 years ago
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Answer:

4.9 eV .

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Ten kilograms of a substance has a latent heat of 1000 J/kg. How much energy does it take to change the phase of this substance?
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10 kL to give energy to the 1000
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Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of
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Answer:

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Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

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