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Vadim26 [7]
4 years ago
5

How is precipitation related to high- and low-pressure air

Physics
1 answer:
pentagon [3]4 years ago
7 0

Answer:

The high-pressure region refers to the condition where the cold and dense air sinks and makes the atmosphere stable, forming clear sky or presence of low clouds in the sky.

On the other hand, the low-pressure region refers to the condition where the hot and less dense air rises upward, and with the presence of a sufficient amount of water content in the air, it gives rise t the formation of the clouds and eventually leads to the occurrence of rainfall.

This is how the process of precipitation is related to the high and the low-pressure air, where the low-pressure zone results in precipitation and high-pressure zone results in a clear sky.

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Answer:

True

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A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.
crimeas [40]

Answer:

Explanation:

Given:

length of ladder r_L = 14m

weight of ladder F_L = 490N

position of firefighter r_F = 3.8m

weight of firefighter F_F = 820N

angle of ladder \alpha = 63

Unknown:

force of the wall on the ladder F_W

force of friction on base of ladder F_R

normal force on base of ladder F_N

From the free body diagram of the sketch you get 3 equations:

F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0

Solving the equations gives:

F_W = F_R\\ F_N = F_F + F_L\\ F_W = \frac{r_FF_F + 0.5r_LF_L}{r_L tan\alpha}

a)

F_R = 238N\\ F_N = 1310N

b)

F_R = \mu F_N\\ \mu = \frac{F_R}{F_N} \\ \mu = 0.3

c) Using the result from b and solving for r_F

\\ \mu = 0.15\\ F_R = \mu F_N\\ r_F = 2.4m

4 0
4 years ago
Why isnt geothermal energy used more often​
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Risk of return on investment is higher than other forms of energy generation.
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If you're walking on the ice cream at 5 ounces per toaster, and your bicycle loses a sock, how much gravy will you need to repai
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3 years ago
An object that completes 20 vibrations in 10 seconds has a frequency of
nika2105 [10]

Answer:

<em> The object has frequency of 2 Hz and time period of 0.5 s.</em>

Explanation:

<em>Frequency</em> is defined as number of oscillation per second ie back and forth swings done in single second.

Here it is given that the object oscillates 20 times in 10 seconds.

So f = \frac{20}{10} = 2Hz

The <em>time period</em> is defined as time taken by the object to complete one full oscillation.

T = \frac{1}{f}

T= \frac{1}{2} =0.5 s

<em>Thus the object has frequency of 2 Hz and time period of 0.5 s.</em>

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