N=2 (always first number), l=1 (corresponds to p), ml=(-1 to 1)
<span> Speicific heat of water is 4.2j/gm*C </span>
<span>Thus 4.2 Joules of energy is required to heat 1 gm water to 1*C. </span>
<span>or 4.2 x 30 Joules enery is required to heat 1x30 gm water by 1*C </span>
<span>or 4.2 x 30 x 80 Joules enery is required to heat 1 x 30 gm water by (100-20)*C( or required to be removed from water to cool it) </span>
Cold, salty water is dense and sinks to the bottom of the ocean while warm water is less dense and remains on the surface. ... Water gets colder with depth because cold, salty ocean water sinks to the bottom of the ocean basins below the less dense warmer water near the surface. In other words it takes a lot of energy to heat water. The specific heat of land is much lower than water. It varies a little by soil type, but it takes a lot less energy to raise the temperature of the same amount of land as water.
Answer:
The answer to your question is empirical formula Al₃O₉S
Explanation:
Data
Al = 31.5 %
O = 56.1 %
S = 12.4 %
Process
1.- Look for the atomic masses of the elements
Al = 27 g
O = 16
S = 32
2.- Represent the percentages as grams
Al = 31.5 g
O = 56.1 g
S = 12.4 g
3.- Convert these masses to moles
27 g of Al ----------------- 1 mol
31.5 g ---------------------- x
x = 1.17 moles
16 g of O ---------------- 1 mol
56.1 g of O ------------- x
x = 3.5 mol
32 g of S --------------- 1 mol
12.4 g of S ------------- x
x = 0.39 moles
4.- Divide by the lowest number of moles
Al = 1.17 / 0.39 = 3
O = 3.5 / 0.39 = 8.9 ≈ 9
S = 0.39 / 0.39 = 1
5.- Write the empirical equation
Al₃O₉S
The answer is B.mass because like the periodic table it determines the elements by mass
