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artcher [175]
3 years ago
11

The bonds of four salts (MgBr2, NaCl, MgCl2, and NaBr) are evaluated for ionic character based on electronegativity differences

between atoms. What is the expected order of these four salts if listed according to bond character from the least ionic character to the greatest ionic character?
Chemistry
1 answer:
sammy [17]3 years ago
6 0

Answer:

MgBr2 < MgCl2 < NaBr < NaCl

Explanation:

In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.

MgBr2 > ΔΕΝ = 1.8

NaCl > ΔΕΝ = 2.3

MgCl2 > ΔΕΝ = 2

NaBr > ΔΕΝ = 2.1

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2) Tin (II) = Sn⁺²

Nitrite = NO₂⁻

So, Tin (II) Nitrate = Sn(NO₂)₂

3) Cobalt (III) = Co⁺³

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4) Titanium (II) = Tn⁺²

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So , Titanium (II) Acetate = Tn(CH₃COO)₂ or Tn(C₂H₃O₂)₂

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So , Vanadium (V) Sulfide = V₂S₅

6) Chromium (III) = Cr⁺³

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So , Chromium (III) Hydroxide = Cr(OH)₃

7) Lithium = Li⁺

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So , Lithium Iodide = LiI

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So , Lead (II) Nitride = Pb₃N₂

9) Silver = Ag⁺

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So , Silver Bromide = AgBr

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