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2 years ago

What is the speed of a wave with a wavelength of 3 m and a frequency of .1hz?

Chemistry

1 answer:

Ivahew [28]2 years ago

4 0

Answer:

0.671081 mps

Explanation:

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Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be

Sphinxa [80]

Answer:

$P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

Explanation:

The first step is:

$P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}$

Second step is:

$P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}$

Multiplying second step by 2, and adding both the steps, we get that:

$P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}$

Cancelling common species, we get that:

$P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

6 0

3 years ago

I need help with 2, 3, and 4 please help i will give the brainliest

Sphinxa [80]

Answer:

2=2.28*10^5

3=3.98*10^3

4=5.76*10^3

8 0

3 years ago

Bond energies do not account for the energy associated with the formation of aqueous solutions. Explain what energy is not accou

Tems11 [23]

Answer:

Why do we all not know the answer to this on the practical

Explanation:

5 0

2 years ago

Please help ASAP! Will mark brainiest if correct

Scilla [17]

Answer: 1 is A

2 is C

3 is D

Hope this help

7 0

2 years ago

A common laboratory reaction is the neutralization of an acid with a base. When 31.8 mL of 0.500 M HCl at 25.0°C is added to 68.

lord [1]

Answer:

The correct answer to the following question will be "90.6 kJ/mol".

Explanation:

The total reactant solution will be:

$(31.8 \ mL+68.9 \ mL)\times 1.07\ g/mL = 107.74 \ g$

The produced energy will be:

$=4.18 \ J/(gK)\times 107.74 \ g\times (28.2-25.0)K$

$=450.35\times 3.2$

$=1441.12 \ J$

The reaction will be:

⇒ $HCl+NaOH \rightarrow NaCl+H_{2}O$

Going to look at just the amounts of reactions with the same concentrations, we notice that they're really comparable.

Therefore, the moles generated by NaCl will indeed be:

= $(\frac{31.8}{1000} \ L)\times (0.500 \ M \ HCl/L)\times \frac{1 \ mol \ NaCl}{1 \ mol \ HCl}$

= $0.0318\times 0.500$

= $0.0159 \ mole \ of \ NaCl$

Now,

= $\frac{1441.12 \ J}{0.0159 \ moles \ NaCl}$

= $906364.7$

= $90.6 \ KJ/mol \ NaCl$

7 0

2 years ago