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3 years ago

When water vapor rises into the atmosphere and begins to condense, it releases ________, the energy of a thunderstorm.

Physics

2 answers:

ANEK [815]3 years ago

7 0

Answer:

A is the correct answer

zubka84 [21]3 years ago

5 0

The answer is latent heat. The specific latent heat of vaporisation, L_v, of a substance is the energy input required for each kilogram to be converted from liquid to gas by evaporation. The 'specific' means per kilogram, so more generally latent heat of vaporisation is the energy taken in during the process for a given mass.

Here we are not vaporising the substance. We are in fact condensing it, the reverse process. All this means is the latent heat is released as electrostatic potential decreases in the water, as opposed to being absorbed. I hope this helps you :)

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PLEASE HELP! LAST DAY TO TURN IN AND IM SO BEHIND!!!

kolbaska11 [484]

<h3>Question 1</h3>

Answer

option C) velocity

Explanation

acceleration = Δv ÷ Δt

<h3>Question 2</h3>

Answer

option C) m/s²

Explanation

Δv ÷ Δt

= m/s ÷ s

= m/s x 1/s

= m/s²

<h3>Question 3</h3>

Answer

option B) velocity has both direction and speed.

That is why velocity can be negative but speed can not and velocity is rate of change of displacement where as speed is rate of change of distance.

7 0

3 years ago

Read 2 more answers

A frictionless pulley used to lift 8000N of concrete. What is the minimum effort required to raise the block

rusak2 [61]

Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

3 0

3 years ago

Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa

anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.

Explanation:

Given that,

First charge $q_{1}= 2.9\mu C$

Second charge $q_{2}= 2.9\mu C$

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

$E_{1}=\dfrac{kq}{r'^2}$

Put the value into the formula

$E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}$

$E_{1}=52200=52.2\times10^{3}\ N/C$

For E₂,

Using formula of electric field

$E_{1}=\dfrac{kq}{r^2}$

Put the value into the formula

$E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}$

$E_{2}=104400=104.4\times10^{3}\ N/C$

We need to calculate the horizontal electric field

$E_{x}=E_{1}\cos\theta$

$E_{x}=52.2\times10^{3}\times\cos45$

$E_{x}=36910.97=36.9\times10^{3}\ N/C$

We need to calculate the vertical electric field

$E_{y}=E_{2}+E_{1}\sin\theta$

$E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45$

$E_{y}=141310.97=141.3\times10^{3}\ N/C$

We need to calculate the net electric field

$E_{net}=\sqrt{E_{x}^2+E_{y}^2}$

Put the value into the formula

$E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}$

$E_{net}=146038.69\ N/C$

$E_{net}=146.03\times10^{3}\ N/C$

We need to calculate the direction of electric field

Using formula of direction

$\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}$

$\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})$

$\theta=75.36^{\circ}$

Hence, The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.

4 0

3 years ago

An object dropped from Cliff falls with a constant acceleration of 10 metre per second square find its Speed of two seconds afte

julsineya [31]

Answer:

20 meters per second

Explanation:

If an object accelerates for 2 seconds, and accelerates by 10 meters per second, then that objects speed will be 20 meters per second, assuming hat there are no other factors involved.

3 0

3 years ago

Read 2 more answers

You measure the power delivered by a battery to be 4.26 W when it is connected in series with two equal resistors. How much powe

gtnhenbr [62]

Answer:

<em>The power delivered by the battery is 17.04 W</em>

Explanation:

Power through a circuit is given as

P = IV ....1

where P is the power

I is the current through the circuit

V is the voltage through the circuit

The voltage in a circuit is given as

V = IR ....2

Let us take the value of each resistor as equal to R

when connected in series, the total resistance will be

$R_{t}$ = R + R = 2R

If we assume constant voltage through the circuit, then from equation 2, the current in this case is

I = V/2R

If the resistors are connected in parallel, then the total resistance will be

$\frac{1}{R_{t} }$ = $\frac{1}{R}$ +

$R_{t}$ = R/2

The current in this case will be increased since the resistance is reduced

I = 2V/R

comparing the two situations, we can see that the current increased when connected in parallel to a ratio of

$\frac{2V}{R}$ ÷ $\frac{V}{2R}$ =

This means that the current increased 4 times

From equation 1, we can see that electrical power is proportional to the current at a constant voltage, therefore, the power will also increase by four times to

P = 4 x 4.26 = <em>17.04 W</em>

3 0

4 years ago