If a large unbalanced force is applied to a stationary low-mass object, what will happen to the object's motion?
1 answer:
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Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.
Explanation:
Given: Mass = 5 kg
Spring constant = 6 N/m
Formula used to calculate period is as follows.
where,
T = period
m = mass
k = spring constant
Substitute the values into above formula as follows.
Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.
Answer:
v = 0.5 m/s
f = 0.42 Hz
ω = 2.6 rad/sec
Explanation:
- By definition, the translational speed is the rate of change of the position with respect to time.
- The change in position along a complete revolution is just the following:
- Δs = 2*π*r = 2*π*0.19 m = 1.19 m
- The time needed to complete a revolution is 2.4 s, so the translational speed can be written as follows:
- The frequency in Hz is just the inverse of the time needed to complete a revolution (known as the period T), as follows:
- f = 1/T = 1/2.4s = 0.42 Hz (2)
- Finally, the angular speed is the rate of change of the angle rotated with respect to time, as follows: