· A hot, just-minted copper coin is placed in 101 g of water to cool. The water

Which type of current flows inside the flashlight A direct B alternating C repeating D pulsating

anzhelika [568]

The flashlight is powered by one or more batteries.
Batteries supply Direct current (DC) .

7 0

3 years ago

The solar mass of the Sun is 1. The orbital period of Jupiter is 11. 9 Earth years. What is the distance between Jupiter and the

cestrela7 [59]

The distance between Jupiter and the sun is 5.2 AU.

According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.

Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.

r =T^2/3

r = (11.9)^2/3

r = 5.2 AU

Learn more: brainly.com/question/15207516

6 0

2 years ago

Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms.

yulyashka [42]

The vertical height from where Jeff dropped the bottle is 10m.

<h3>What is free falling?</h3>

When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy(P.E) of

U =mgh

When the object strikes the ground, all the potential energy converted into kinetic energy.

k.E = 1/2mv²

where v is the speed just before hitting the ground.

From energy conservation principle, initial and final mechanical energy are equal.

mgh = 1/2mv²

Given is Jeff climbs a hill. He drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground.

The height from which bottle could fall is

h = v²/2g

Substitute the values, we get

h = (14)²/(2x9.81)

h =9.99 m

Thus, vertical height from where Jeff dropped the bottle is approximately 10m.

Learn more about free falling.

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8 0

2 years ago

A.) A bullet accelerates at 8000 m/s2

lukranit [14]

Answer:

0.02 s

160 m/s

Explanation:

Given:

Δx = 1.6 m

v₀ = 0 m/s

a = 8000 m/s²

A) Find t.

Δx = v₀ t + ½ at²

1.6 m = (0 m/s) t + ½ (8000 m/s²) t²

t = 0.02 s

B) Find v.

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (8000 m/s²) (1.6 m)

v = 160 m/s

6 0

3 years ago

A car is moving with a constant speed v around a level curve. The coefficient of friction between the tires and the road is 0.40

Salsk061 [2.6K]

Answer:

Minimum radius of the curve to stay on the road will be equal to $0.255v^2m$

Explanation:

We have given coefficient of kinetic friction $\mu =0.40$

Acceleration due to gravity $g=9.8m/sec^2$

We have to find minimum radius of the curve so that car will stay on the road

For the car to stay on the road centripetal force must be equal to frictional force

So $\frac{mv^2}{r}=\mu mg$

So minimum radius of the

$r=\frac{v^2}{\mu g}=\frac{v^2}{0.4\times 9.8}=0.255v^2m$

So minimum radius of the curve to stay on the road will be equal to $0.255v^2m$

8 0

3 years ago