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olga_2 [115]
2 years ago
7

How many grams of lithium are needed to produce 45.0g of lithium nitride?

Chemistry
1 answer:
german2 years ago
6 0

Answer:

              26.899 g of Li

Solution:

The Balance Chemical Equation for given reaction is as follow;

                                         6 Li  +  N₂    →    2 Li₃N

According to equation,

                 69.66 g (2 mol) Li₃N is produced by  =  41.64 g (6 mol) of Li

So,

                    45.0 g of Li₃N will be produced by  =  X g of Li

Solving for X,

                      X =  (45.0 g × 41.64 g) ÷ 69.66 g

                      X  =  26.899 g of Li

Hence, 26.9 g of Lithium is required to produce 45.0 g of Lithium Nitride.

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2 years ago
Food contains a sugar called , which is broken down in a process called cellular . This process uses to break down food molecule
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glucose

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4 0
3 years ago
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Hydrogen may not be advantagous as a fuel because-------
sergeinik [125]

Answer:

Hydrogen may not be advantageous as a fuel because...

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Explanation:

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7 0
3 years ago
How many significant figures in 0.002030?
scoundrel [369]
Answer:
Three.
Explanation:
When counting the number of significant figures in a decimal number, you start counting from the right of the decimal point.
0
.00203
Counting from left to right from the decimal point , there are 5 digits.
However, the zeroes before any natural number is not counted as a significant figure.
0.00
203
Thus, there are
3
significant figures ie. 203.
Note: any other numbers added to the right of
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8 0
3 years ago
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A 25-liter sample of steam at 100°c and 1.0 atm is cooled to 25°c and expanded until the pressure is 19.71 mmhg. if no water con
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I will use [pV/T] in the state 1 = [pV/T] in the state 2.

State 1:
p = 1.0 atm
V = 25 liter
T = 100 + 273.15 = 373.15 K

State 2:

p = 19.71 mmHg * 1.atm / 760 mmHg = 0.0259atm
V= ?
T = 25 + 273.15 = 298.15 K

Application of the formula

1.0 atm * 25 liter / 373.15 k = 0.0259 atm * V / 298.15 K =>
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3 years ago
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