Draw the curved arrow mechanism to show the conversion of hex-1-ene and CH3CH2OH in acidic solution into 2-ethoxyhexane. Follow
the given instructions for each step. Draw all necessary atoms and charges; do not add any structures.
1 answer:
Answer:
The formation of ether from alkene and alcohol in the presence of an acid take place in four steps.
Step 1:
In first step the oxygen atom of alcohol abstracts the proton of acid and becomes a strong conjugate acid.
Step 2:
Double bond of alkene being electron rich and nucleophilic in nature adds the proton from alcohol across its double bond and forms a stable carbocation (i.e. in this case a 2° carbocation).
Step 3:
The oxygen atom of alcohol now attacks the electrophilic carbon (i.e. carbocation).
Step 4:
The conjugate base of acid catalyst formed in first step abstracts the proton from oxonium ion and allows the final product to form as shown in attached reaction mechanism.
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Answer: The new pressure of the gas in Pa is 388462
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas at STP =
= final pressure of gas = ?
= initial volume of gas = 700.0 ml
= final volume of gas = 200.0 ml
= initial temperature of gas = 273 K
= final temperature of gas =
Now put all the given values in the above equation, we get:
The new pressure of the gas in Pa is 388462
Answer:
a) No molecules of hydrogen
b) four molecules of ammonia
c) four left molecules of nitrogen.
Explanation:
The balanced reaction between nitrogen and hydrogen molecules to give ammonia molecules is:
Thus one molecule of nitrogen will react with three molecules of hydrogen to give two molecules of ammonia.
We have six molecules of each nitrogen and hydrogen in the closed container and they undergo complete reaction it means the limiting reagent is hydrogen. For six molecules of nitrogen, eighteen molecules of hydrogen will be required.
So six molecules of hydrogen will react with two molecules of nitrogen to give four molecules of ammonia.
The product mixture will have
a) No molecules of hydrogen
b) four molecules of ammonia
c) four left molecules of nitrogen.